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3 years ago

A car travels from rest to 55 m/s in 10 seconds. What is its acceleration?

Physics

1 answer:

maria [59]3 years ago

5 0

Answer:

(55-0)/10 --> 55 m/s / 10 s --> 5.5 m/s^2

Explanation:

I WANT U TO PARK THAT BIG MACK TRUCK, RIGHT IN THIS LITTLE GRAGE

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Area of land drained by a water system

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3 years ago

Is it true that if an object is moving it has kinetic energy

densk [106]

Yes an object in motion has kinetic energy

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3 years ago

Read 2 more answers

A motorcycle is travelling at a constant velocity of 30ms. The motor is in high gear and emits a hum of 700Hz. The speed of soun

timurjin [86]

Answer:

a) $T=1.43\times 10^{-3}\ s$

b) $d=0.0429\ m$

c) $\lambda=0.4857\ m$

d) $f_o=767.7\ Hz$

Explanation:

Given:

velocity of the sound from the source, $S=340\ m.s^{-1}$

original frequency of sound from the source, $f_s=700\ Hz$

speed of the source, $v_s=30\ m.s^{-1}$

(a)

We know time period is inverse of frequency:

Mathematically:

$T=\frac{1}{f}$

$T=\frac{1}{700}$

$T=1.43\times 10^{-3}\ s$

(b)

Distance travelled by the motorcycle during one period of sound oscillation:

$d=v_s.T$

$d=30\times 1.43\times 10^{-3}$

$d=0.0429\ m$

(c)

The distance travelled by the sound during the period of one oscillation is its wavelength.

$\lambda=\frac{S}{f}$

$\lambda=\frac{340}{700}$

$\lambda=0.4857\ m$

(d)

observer frequency with respect to a stationary observer:

<u>According to the Doppler's effect:</u>

$\frac{f_o}{f_s}= \frac{S+v_o}{S-v_s}$ ...........................(1)

where:

$f_o\ \&\ v_o$ are the observed frequency and the velocity of observer respectively.

Here, observer is stationary.

$\therefore v_o=0\ m.s^{-1}$

Now, putting values in eq. (1)

$\frac{f_o}{700}= \frac{340+0}{340-30}$

$f_o=767.7\ Hz$

5 0

3 years ago

22. (I) A car slows down from 28 m/s to rest in a distance of

lidiya [134]

Answer:

a = -8.912 m/s²

Explanation:

Given,

The initial velocity of the car, u = 28 m/s

The final velocity of the car, v = 0

The distance traveled by car, d = 88 m

The velocity displacement relation is given by the formula

v = d/t

∴ t = d/v

Substituting in the above values in the given equation

t = 88/28

= 3.142 s

The acceleration is given by the formula

a = (v-u)/t

= (0 - 28)/3.142

= -8.912 m/s²

The negative sign is that the car is decelerating.

Hence, acceleration a = -8.912 m/s²

7 0

3 years ago

How many carbon atoms are there in 5 molecules of CHCl3?

lukranit [14]

There are 5 carbon atoms present in the Chemical formula, $CHCl_\\{3}$ .

<h3>What is a chemical formula?</h3>

A chemical formula is used to show the number and type of atoms present in a molecule, using the atomic symbols of the elements and numerical subscripts.

From the chemical formula;

We can deduce that we have the following elements and their corresponding number of atoms in one molecule of the compound;

Carbon = 1 atom

Hydrogen = 1 atom

Chlorine = 3 atoms

So, in 5 molecules of the compound;

Carbon = 1 x 5 = 5 atoms

Hydrogen = 1 x 5 = atoms

Chlorine = 3 x 5 atoms = 15 atoms

In conclusion, from the solution above, we can say that we have 5 atoms of carbon present in 5 molecules of $CHCl_3$ .

Learn more about chemical formula:brainly.com/question/26388921

#SPJ1

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1 year ago