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3 years ago

I'm really tired so please help

Physics

1 answer:

Taya2010 [7]3 years ago

3 0

So that the bridge doesn't break when the summer comes and It expands Or when winter comes and it contracts

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Two ropes are attached to a 35 kg object. The first rope applies a force of 20 N and the second applies a force of 55 N. If the

Goshia [24]

Answer:

$a=1.672\ m.s^{-2}$

Explanation:

Given:

mass of the object, $m=35\ kg$

forces by two mutually perpendicular ropes of the attached to the object:

$F_x=20\ N$

$F_y=55\ N$

Now we find the resultant force effect due to the two given forces:

$F=\sqrt{F_x^2+F_y^2}$

$F=\sqrt{(20)^2+(55)^2}$

$F=58.52\ N$

Now the acceleration will be due to this resultant force:

$a=\frac{F}{m}$

$a=\frac{58.52}{35}$

$a=1.672\ m.s^{-2}$

3 0

3 years ago

Read 2 more answers

a chemical reaction a temperature change may occur because of the breaking or formation of chemical bonds that release excess en

Hoochie [10]

Answer:

it cannot be considered a physical change because it occur from the chemical reaction.

Explanation:

because physical change is the change of the size,volume, density,flexibility. in other words its a change in the outer appearance or change in which we can see or feel without using a tool or a machine

hope it help just my opinion

5 0

3 years ago

How does regular exercise help older adult stay healthy?

gtnhenbr [62]

It’s helps the heart stay healthier by respiratory of the heart

5 0

3 years ago

Read 2 more answers

To measure the height of a building without a ruler or tape measure, an engineer drops a rock off the top of the building and fi

serg [7]

The relevant equation we can use in this problem is:

h = v0 t + 0.5 g t^2

where h is height, v0 is initial velocity, t is time, g is gravity

Since it was stated that the rock was drop, so it was free fall and v0 = 0, therefore:

h = 0 + 0.5 * 9.81 m/s^2 * (4.9 s)^2

h = 117.77 m

6 0

3 years ago

A satellite is in orbit 36000km above the surface of the earth. Its angular velocity is 7.27*10^-5 rad/s. What is the velocity o

bagirrra123 [75]

Answer:

v = 3.08 km/s

Explanation:

Given that,

The angular velocity of the satellite = $\omega=7.27\times 10^{-5} rad/s$

A satellite is in orbit 36000km above the surface of the earth.

The radius of the earth is 6400 km

Let v is the velocity of the satellite. It can be calculated as :

$v=r\omega\\\\v=(36000\times 10^3+6400\times 10^3)\times 7.27\times 10^{-5}\\\\v=3082.48\ m/s\\\\v=3.08\ km/s$

So, the velocity of the satellite is 3.08 km/s.

6 0

3 years ago