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bekas [8.4K]
3 years ago
14

Where are the magnetic fields strongest near a bar magnet?

Physics
2 answers:
DENIUS [597]3 years ago
8 0

Its at the ends

Explanation:↑↑↑↑↑↑↑↑↓↓↓↓↓↓↓↓↓⇔⇔⇔⇔⇔⇔⇔⇔⇔⇔⇔⇔⇔⇔⇔⇔⇔⇔⇔⇔⇆⇆⇆⇆⇆⇆⇆⇆⇆⇄⇄⇄⇄⇄⇄⇄⇄⇄⇄⇅⇅⇅⇅⇅⇅⇅⇵⇵⇵⇵⇵⇵⇵

KatRina [158]3 years ago
3 0
The answer is near the poles.
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Do frictional forces act in the same direction or in the opposite direction to the applied force?
Evgesh-ka [11]

Frictional forces act in the direction opposite to the MOTION. That direction could be the same OR opposite to applied force.

-- If you push a loaded heavy wagon from behind, trying to get it going faster, friction is acting against you, opposite to your force.

-- If you push a loaded rolling heavy wagon from in front, trying to make it slow down, friction is acting with you, in the same direction as your force.

-- Opposite to the motion both times.

3 0
3 years ago
The field around a solenoid is similar to the field around a bar magnet.<br><br> true or false?
OlgaM077 [116]
The answer would be true :)
8 0
3 years ago
An electron of mass 9.11×10-31kg leaves one end of a TV picture tube with zero initial speed and travels in a straight line to t
SOVA2 [1]

Answer:

(A) Acceleration will be 240.3846\times 10^{12}m/sec^2

(b) Time taken will be 1.4\times 10^{-8}sec

(c) Force will be 2189.9\times 10^{-19}N              

Explanation:

We have given that electron starts from rest so initial velocity u = 0 m/sec

Final velocity v=2.50\times 10^6m/sec

Mass of electron m=9.11\times 10^{-31}kg

Distance traveled by electron s=1.30cm =0.013m

From third equation of motion we know that v^2=u^2+2as

(a) So (2.5\times 10^6)^2=0^2+2\times a\times 0.013

a=240.3846\times 10^{12}m/sec^2

(b) From first equation of motion we know that v = u+at

So 2.50\times 10^6=0+240.3846\times 10^{12}t

t=0.014\times 10^{-6}=1.4\times 10^{-8}sec

(c) From newton's law we know that force

F=ma=9.11\times 10^{-31}\times 240.3846\times 10^{12}=2189.9\times 10^{-19}N

7 0
3 years ago
The diagram shows a wave moving from one medium to another
Shtirlitz [24]

As the speed of wave decreases, the wavelength of the wave decreases.

<h3>Refraction</h3>

We know that as a wave travels from one medium to another its speed decreases depending on if the first medium is less dense than the second medium or increases depending on if the first medium is more dense than the second medium. This is known as refraction

Now, we know that the speed of a wave v = fλ where

  • f = frequency and
  • λ = wavelength. Since f is constant, v ∝ λ.

The ratio of the speed in medium one to speed in medium two is called the refractive index of medium 1 to 2.

<h3>Explaining the diagram</h3>

From the diagram, we see that the wavelength in medium 1 is longer than that in medium 2. Since wavelength and speed are proportional, so the speed in medium 1 is also greater than the speed in medium 2.

So, As the speed of wave decreases, the wavelength of the wave decreases.

Learn more about refraction here:

brainly.com/question/25758484

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2 years ago
Being rejected by a peer group can negatively influence one's self-esteem
exis [7]
Yes. Amen. Tell me about it.
8 0
3 years ago
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