Question

A parcel is traveling on a horizontal conveyer belt moving at 1 meter/second. At the end of the conveyor belt, the parcel lands on a tray after 1 second. Calculate the horizontal and vertical distance of the tray from the end of the conveyor belt.
A) 1.9 meters, 2.3 meters
B)1 meter, 4.9 meters
C)3.2 meters, 1.2 meters
D)3.3 meters, 4.3 meters
E)9.8 meters, 4.2 meters

Answer 1

Assume the acceleration due to gravity is approximately 9.8 m/s^2

In 1 second, it will fall

s = ut + at^2/2

u = initial vertical velocity = 0

a = 9.8

t = 1

s is the distance it falls

= 9.8/2 = 4.9 m

But the parcel has a horizontal velocity of 1 m/s so it will travel 1 m horizontally in 1 second.

The answer would be

1 metre, 4.9 metres.