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marishachu [46]
3 years ago
11

Can someone explain how exactly to calculate the net force? Do you subtract the smaller number from the larger number? Any help

would be appreciated!

Physics
1 answer:
aleksley [76]3 years ago
3 0

Explanation:

Let's say right is positive and left is negative.

F₁ = -150 N

F₂ = 220 N

Fnet = F₁ + F₂

Fnet = -150 N + 220 N

Fnet = 70 N

The magnitude of Fnet is 70 N, and since it's positive, the direction is to the right.

And since Fnet isn't 0, the force is unbalanced and the motion is changing.

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A copper transmission cable 180 km long and 11.0 cm in diameter carries a current of 135 A.
zheka24 [161]

Answer:

a) 43.98 V

b) E = 21.37 MJ

Explanation:

Parameters given:

Length of cable = 180 km = 180000 m

Diameter of cable = 11 cm = 0.11 m

Radius = 0.11 / 2 = 0.055 m

Current, I = 135 A

a) To find the potential drop, we have to find the voltage across the wire:

V = IR

=> V = IρL / A

where R = resistance

L = length of cable

A = cross-sectional area

ρ = resistivity of the copper wire = 1.72 * 10^(-8) Ωm

Therefore:

V = (135 * 1.72 * 10^(-8) * 180000) / (π * 0.055^2)

V = 43.98 V

The potential drop across the cable is 43.98 V

b) Electrical energy is given as:

E = IVt

where t = time taken = 1 hour = 3600 s

Therefore, the energy dissipated per hour is:

E = 135 * 43.98 * 3600

E = 21.37 MJ (mega joules, 10^6)

7 0
3 years ago
Given that average speed is distance traveled divided by time, determine the values of m and n when the time it takes a beam of
SashulF [63]

The distance  of earth from sun is 150 million km

We know that one million = 10^6 and 1 km= 10^3 m

Hence 150 million km = 150× 10^6 ×10^3 metre=150×10^9 m

                                                                                  =1.5×10^11 m

The speed of light in vacuum is  2.999... m/s which can be approximately close to  3.0 ×10^8 m/s

We are asked to calculate the time taken by the light beam to reach from sun to earth.

we know that average velocity v=\frac{distance}{time}

                                                       ⇒ time= \frac{distance}{velocity}

Here distance=1.5×10^11 m and v=c= 3.0×10^8 m/s

                            hence time [t]=\frac{1.5*10^{11} }{3.0*10^{8} } second

                                                           =0.5×10^3 s

                                                            =5.0×10^2 s

 A correct scientific notation  is written as m×10^n   [Here m is the magnitude and n is power of 10]                                                      

Hence the value of m =5 and value of n =2



3 0
4 years ago
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The production of carbon dioxide might be an indicator of what process
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Its a proces of combustion "burning"humans produce carbon dioxide,rocks<plants whatever is burning energy
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3 years ago
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Students create a standing wave with three loops on a slinky 3.75 m longThey time 20 oscillations in 6.73 . What frequency would
yaroslaw [1]

Answer:

f = 4.95\ hz

Explanation:

Given,

Student create wave of three loop on a slinky 3.75 m.

number of oscillations= 20

Time, t = 6.73 s

Frequency = \dfrac{20}{6.73}

                  = 2.97 Hz

We need to find frequency when 5 loops is created.

f = \dfrac{5}{3} \times 2.97

f = 4.95\ hz

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Linda has a cup of coffee sitting in the cup holder in her car. She has to suddenly slam on her brakes and stop. The cup remaine
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Newton's law of inertia says that an object at rest will stay at rest and an object in motion will stay in motion. The coffee was moving the same speed as the car and continued to do so even after the car itself had stopped.
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