Answer: 233 L of 
will be produced from 150 grams of 
Explanation:
To calculate the moles :
The balanced chemical equation is:
According to stoichiometry :
2 moles of produce = 8 moles of
Thus 2.59 moles of will produce=
of
Volume of 
Thus 233 L of will be produced from 150 grams of
<span>A compound which is called ionic compound dissociates
into ions when in aqueous solution. These ions move freely in the solution and
can allow the flow of electricity into the solution. These ions contains a certain charge or what is called the oxidation number.</span>
<span>200 moles
The balanced equation for creating water from hydrogen and oxygen gas is
2H2 + O2 => 2H2O
So for every mole of oxygen gas, you need two moles of hydrogen. So looking that the amount of oxygen and hydrogen you have, it's obvious that oxygen is the limiting reactant since 100 moles of oxygen will consume 200 moles of hydrogen. While 210 moles of hydrogen requires 105 moles of oxygen.
Now for each mole of oxygen gas you use, you create 2 moles of water. So
100 mol * 2 = 200 mol
So you can create 200 moles of water from the given amounts of reactants.</span>
Answer:
a free swimming larval stage in which a parasitic fluke passes from an intermediate host to another intermediate host
Answer:
Because we need to dispense 4.7 mL, the volume reading in the pipet is the 5.3 mL line.
Explanation:
First we use C₁V₁=C₂V₂ in order to <u>calculate the required volume of concentrated HCl</u> (V₁):
12.85 M * V₁ = 0.600 M * 100 mL
V₁ = 4.7 mL
<u>So we need to dispense 4.7 mL of the concentrated HCl solution</u>. The mark in the pipet that would contain that volume would be 10.0 - 4.7 = 5.3 mL
