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inna [77]
3 years ago
6

In the reaction between copper sulphate solution and sodium sulphide solution, 15.9 g copper sulphate completely reacts with 7.8

g of sodium sulphide. It is observed that 9.5 g of copper sulphide is formed. What is the mass of sodium sulphate solution formed?
Chemistry
1 answer:
nikitadnepr [17]3 years ago
8 0

Answer:

The mass of formed sodium sulphate solution is 14.2 g.

Explanation:

From the given,

Mass of copper sulphate = 15.9 g

Mass of sodium sulphide = 7.8 g

Total mass of reactant  =  Mass of copper sulphate + Mass of sodium sulphide

                                     = 15.9 + 7.8g = 23.7g

Mass of copper sulphide formed = 9.5 g

Mass of sodium sulphate = Total mass - Mass of copper sulphide

                                          = 23.7 g - 9.5 g = 14.2 g

Therefore, The mass of formed sodium sulphate solution is 14.2 g.

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Answer:

The net change in enthalpy for the formation of one mole of acrylic acid from calcium carbide, water and carbon dioxide is 523.2 kJ.

Explanation:

Step 1:

CaC_2(s) + 2H_2O(g)\rightarrow C_2H_2(g) + Ca(OH)_2(s),\Delta H_1=414.0 kJ...[1]

Step 2 :

6C_2H_2(g) + 3CO_2(g) + 4H_2O(g)\rightarrow 5CH_2CHCO_2H(g) \Delta H_2=132.0kJ..[2]

Adding 6 × [1] and [2]:

6CaC_2(s) + 12H_2O(g)\rightarrow 6C_2H_2(g) + 6Ca(OH)_2(s)

6C_2H_2(g)+3CO_2(g)+16H_2O(g)\rightarrow 5CH_2CHCO_2H(g)

we get :

6CaC_2(s) + 8H_2O(g)+3CO_2(g)\rightarrow 5CH_2CHCO_2H(g)+ 6Ca(OH)_2(s),\Delta H'=?

\Delta H'=6\times \Delta H_1+\Delta H_2

\Delta H'=6\times 414.0 kJ+132.0kJ

\Delta H'=2,626 kJ

Energy released on formation of 5 moles of acrylic acid = 2,626 kJ

Energy released on formation of 1 mole of acrylic acid:

\frac{ 2,626 kJ}{5 } = 523.2 kJ

7 0
3 years ago
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