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scoundrel [369]
3 years ago
10

A fire hose is turned on the door of a burning building in order to knock the door down. This requires a force of 1000 N. If the

hose delivers 40 kg per second, what is the minimum velocity of the stream needed, assuming the water doesn't bounce back?
Physics
1 answer:
Sedaia [141]3 years ago
8 0

Answer:

Minimum velocity is 25m/s

Explanation:

Given force F =1000N

Mass flow rate m/t= 40kg/s

Velocity=v

Recall Newton second law of motion F =MV/t

1000=40v

V=1000/40

25m/s

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Answer:

The number of turns in the solenoid is 230.

Explanation:

Given that,

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Magnetic flux, \phi=0.00338\ Wb

The induced emf through the solenoid is given by :

\epsilon=L\dfrac{dI}{dt}

or

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The self inductance of the solenoid is given by :

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From equation (1) and (2) we get :

\dfrac{\epsilon}{(di/dt)}=\dfrac{N\phi}{I}

N is the number of turns in the solenoid

N=\dfrac{\epsilon I}{\phi (dI/dt)}

N=\dfrac{12.4\times 10^{-3}\times 1.5}{0.00338 \times 0.024}

N = 229.28 turns

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N = 230 turns

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