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3 years ago

30 POINTS PLEASE HELP ASAP

Chemistry

1 answer:

lina2011 [118]3 years ago

4 0

Hello!

We have the following data:

f (radiation frequency) = $3.0*10^{19}\:Hz$

v (speed of light) = $3.0*10^8\:m/s$

λ (wavelength) = ? (in m)

Let's find the wavelength, let's see:

$f = \dfrac{v}{\lambda}$

$3.0*10^{19} = \dfrac{3.0*10^8}{\lambda}$

$\lambda = \dfrac{3.0*10^8}{3.0*10^{19}}$

$\boxed{\boxed{\lambda = 1*10^{-11}\:m}}\Longleftarrow(wavelenght)\end{array}}\qquad\checkmark$

I Hope this helps, greetings ... DexteR! =)

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The mass percent of Hexane in solution is 83.51%

Explanation:

Take 1 kg basis for the vapor: 35.5 mass% pentane = 355 g pentane with 645 g hexane.

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From Raoult's law we know:

Pp = xp $\times$ Pp - vap = yp $\times$ Pt (1)

Ph = xh $\times$ Ph - vap = yh $\times$ Pt (2)

Since it is a binary mixture we can write xh = (1 - xp) and yh = (1 - yp), therefore (2) becomes:

(1 - xp) $\times$ Ph - vap = (1 - yp) $\times$ Pt (3)

Substituting (1) into (3) we get:

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xp = Ph - vap / (Pp - vap/yp - Pp - vap + Ph - vap) (5)

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Pentane mol% in solution: xp = 19.08%

Hexane mol% in solution: xh = 80.92%

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mp = 0.1908 mol $\times$ 72.15 g/mol

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Mass% of Pentane solution = 13.766/(13.766+69.737)

= 16.49%

Mass% of Hexane solution = 83.51%

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