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Arisa [49]
3 years ago
11

The first American to orbit the earth was:

Physics
2 answers:
Brums [2.3K]3 years ago
8 0

Yes, John Glenn was the first to orbit the earth but the question I read was who WALKED ON THE MOON.....the answer to who was the FIRST to walk on the moon... is  Neil Armstrong but Buzz Aldrin also walked and was there with Armstrong but wasn't the first.  You have to be careful about the astronaut 'firsts'.  Alan Shepherd was the first in space....John Glenn was the first to orbit the earth....Edward White was the first to 'walk in space' and Neil Armstrong was the first man to walk on the moon. Also remember that all of these were American Astronaut firsts.  The Russians actually put up the first man in space.  Yuri Gagarin was the first man.  Buzz Aldrin landed and walked on the moon also.

alexdok [17]3 years ago
3 0
John Glenn is the first American to orbit the Earth.

<span>♡♡Hope I helped!!! :)♡♡
</span>
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Dans un tube en U contenant du mercure ,on verse de l'autre côté de l'acide sulfurique de densité 1,84 et de l'autre côté de l'a
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Explanation:

Unclear question. The clear rendering reads;

"Into a U-tube containing mercury, pour on the other side sulfuric acid of density 1.84 and on the other side alcohol of density 0.8 so that the levels are in the same horizontal plane. The height of the acid above the mercury being 24 cm. What is the height of the bar and what variation of the level of the acid, when the mercury density is 13.6?

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3 years ago
The potential energy of a negative charge moved from point A to point B will increase.A negative charge moved from point A to po
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Answer:

<em>The K.E from A to B won't increase...</em>

Explanation:

That's because the P.E from A to B is increasing. The K.E will increase if charge moves from a higher potential to a lower potential i.e., from B to A.

That is the reason there is no effect on net K.E when moving from a potential to same potential over and over (A to C).

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The larger the push, the larger the change in velocity. This is an example of Newton's Second Law of Motion which states that th
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How much work must be done to bring three electrons from a great distance apart to 3.0×10−10 m from one another (at the corners
Natasha_Volkova [10]

Answer:

Potential\ Energy=Work \ Done=2.301*10^{-18} J

Work  done to bring three electrons from a great distance apart to 3.0×10−10 m from one another (at the corners of an equilateral triangle) is 2.301*10^{-18} Joules

Explanation:

The potential energy is given by:

U=Q*V

where:

Q is the charge

V is the potential difference

Potential Difference=V=\frac{kq}{r}

So,

Potential\ Energy=\frac{Qkq}{r} \\Q=q\\Potential\ Energy=\frac{kq^2}{r}

Where:

k is Coulomb Constant=8.99*10^9 Nm^2/C^2

q is the charge on electron=-1.6*10^-19 C

r is the distance=3.0*10^{-10}m

For 3 Electrons Potential Energy or work Done is:

Potential\ Energy=3*\frac{kq^2}{r}

Potential\ Energy=3*\frac{(8.99*10^9)(-1.6*10^{-19})^2}{3*10^{-10}}\\Potential\ Energy=2.301*10^{-18} J

Work  done to bring three electrons from a great distance apart to 3.0×10−10 m from one another (at the corners of an equilateral triangle) is 2.301*10^{-18} Joules

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