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Arisa [49]
3 years ago
11

The first American to orbit the earth was:

Physics
2 answers:
Brums [2.3K]3 years ago
8 0

Yes, John Glenn was the first to orbit the earth but the question I read was who WALKED ON THE MOON.....the answer to who was the FIRST to walk on the moon... is  Neil Armstrong but Buzz Aldrin also walked and was there with Armstrong but wasn't the first.  You have to be careful about the astronaut 'firsts'.  Alan Shepherd was the first in space....John Glenn was the first to orbit the earth....Edward White was the first to 'walk in space' and Neil Armstrong was the first man to walk on the moon. Also remember that all of these were American Astronaut firsts.  The Russians actually put up the first man in space.  Yuri Gagarin was the first man.  Buzz Aldrin landed and walked on the moon also.

alexdok [17]3 years ago
3 0
John Glenn is the first American to orbit the Earth.

<span>♡♡Hope I helped!!! :)♡♡
</span>
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2.<br> ___ ___ is the number of wavelengths that pass a given point/second.
atroni [7]

Answer:

frequency tell me if im right

Explanation:

5 0
3 years ago
How to find i1, i2,i3
MrRissso [65]

to find i1, i2, and i3 we need to find the total current.

to find the total current, you need to find the total resistance

you're already given the total voltage, Vs

to find Rtotal, start from the resistors furthest from the voltage source.

R3 and R4 are in series so

Rtotal= R3+R4 = 6+3 = 9 ohms

9 ohms is now in parallel with R2 so,

Rtotal= (\frac{1}{R3+R4}) ^{-1}\\ + (\frac{1}{R2}) ^{-1})^-1= (1/18)^-1 +( 1/9)^-1 = 6 ohms

6 ohms is in series with R1 so

Rtotal=  4+6=10 ohms

itotal= (\frac{Vtotal}{Rtotal})

= 120 v/10 ohms = 12 A

i total = i1 because all the current flows through it

i1= 12A

so the current splits into i2 and i3 and the amount of current that flows through a branch depends on the total resistance in each branch.

we already calculated the resistance in the R3+R4 & R2 branch as 6 ohms

since r3 and r4 are in series, the same current will flow through them

r3+r4 = 9 ohms

r2= 18 ohms

so the current in r2 will be half that of R3 & R4 (V=IR)

using the current divider rule

Ix = Itotal * \frac{Rtotal}{Rx}

i2= 12A x (6 ohms/18 ohms)= 4 A

i3= 12A x (6 ohms/9 ohms) = 8 ohms

6 0
3 years ago
What happens when a light ray is parallel to the principal axis ?
Phantasy [73]

Answer:

Any incident ray traveling parallel to the principal axis of a converging lens will refract through the lens and travel through the focal point on the opposite side of the lens. ... These rays of light will refract when they enter the lens and refract when they leave the lens.

Hope this helps...

7 0
3 years ago
What has been something positive for you that has been a result of social distancing? (Answer thoughtfully and throughly.)
Sunny_sXe [5.5K]

Answer: I have more time to think about the wonderful things in life that we don't always appreciate.

Explanation:

3 0
3 years ago
Read 2 more answers
Two ions with masses of 4.39×10−27 kg move out of the slit of a mass spectrometer and into a region where the magnetic field is
Ilia_Sergeevich [38]

Answer:

7.2 cm

Explanation:

magnetic field, B = 0.301 T

speed, v = 7.92 x 10^5 m/s

mass, m = 4.39 x 10^-27 kg

q = 1.6 x 10^-19 C

The radius of singly changed ion is given by

r = \frac{mv}{Bq}

where, m is the mass of ion, v be the speed of ion, B is the magnetic field and q be the charge

r = \frac{4.39\times 10^{-27}\times 7.92 \times 10^{5}}{0.301\times 1.6\times 10^{-19}}

r = 0.072 m

r = 7.2 cm

5 0
3 years ago
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