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tigry1 [53]
3 years ago
8

Charges of +2 µC and +3 µC are 4 mm from each other. Raina’s group draws four diagrams trying to represent the electrical force

between the charges.
Which diagram is correct?

A) W
B) X
C) Y
D) Z

Physics
2 answers:
Lyrx [107]3 years ago
5 0

The correct diagram would be A) W

maria [59]3 years ago
4 0

Answer: The correct answer is option A.

Explanation:

When two like charges come closer to each other they will repel each other.

When two unlike charges come closer to each other they will attract.

q_1=+2\mu C,q_2=+3\mu C

Force on q_1 due to q_2:

F_{12}=k\frac{q_1\times q_2}{r^2}

Force on q_2 due to q_3:

F_{21}=k\frac{q_2\times q_1}{r^2}

F_{12}=F_{21}

Therefore, equal force is exerting on both the charges. The diagram drawn by Raina marked "W" is correct. Hence the correct option is (A).

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AlladinOne [14]

Answer:

The tension in the rope is 262.88 N

Explanation:

Given:

Weight W = 150 N

Length of rope r = 4.1 m

Initial speed of ball v = 5.5 \frac{m}{s}

For finding the tension in the rope,

First find the mass of rod,

mg = 150                          ( g = 9.8 \frac{m}{s^{2} } )

  m = \frac{150}{9.8}

  m = 15.3 kg

Tension in the rope is,

  T = mg + \frac{mv^{2} }{r}

  T = 150 + \frac{15.3 \times (5.5)^{2} }{4.1}

  T = 262.88 N

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The position x, in meters, of an object is given by the equation:
LenaWriter [7]

Answer:

The SI units of A, B and C are :

m,\ m/s\ and\ m/s^2                  

Explanation:

The position x, in meters, of an object is given by the equation:

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Where

t is time in seconds

We know that the unit of x is meters, such that the units of A, Bt and Ct^2 must be meters. So,

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b=\dfrac{m}{s}=m/s

  • Ct^2=m

C=m/s^2

So, the SI units of A, B and C are :

m,\ m/s\ and\ m/s^2

So, the correct option is (B).

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