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Jet001 [13]
3 years ago
13

Which of the following is one way to prevent the corrosion of iron? 

Chemistry
1 answer:
Drupady [299]3 years ago
4 0
B: Painting over a metal surface in order to prevent rust is known as rust proofing and it works by preventing oxygen and water from reaching the metal surface thus preventing a redox reaction which would result in rusting.
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Prospectors are considering searching for gold on a plot of land that contains 2.45 g of gold per bucket of soil. If the volume
makvit [3.9K]

Answer:

13.2 g of gold

Explanation:

We'll begin by converting 5.25 L to ft³.

This can be obtained as follow:

Recall:

1 L = 0.0353 ft³

Therefore,

5.25 L = 5.25 × 0.0353

5.25 L = 1.85×10¯¹ ft³

From the question given above,

2.45 g of gold is present in 5.25 L ( i.e 1.85×10¯¹ ft³) of soil.

Therefore, Xg of gold will be present in 1 ft³ of soil i.e

Xg of gold = 2.45/1.85×10¯¹

Xg of gold = 13.2 g

Therefore, 13.2 g of gold is present in 1 ft³ of the soil.

8 0
3 years ago
Please help!!!!!<br> 50 points for this!!!!!!!!!!
anzhelika [568]

When a molecule of oxygen (O2) is combined with an atom of carbon (C), they form CO2, or carbon dioxide. The carbon and oxygen are the reactants in this chemical reaction; the CO2 is the product.

5 0
3 years ago
Read 2 more answers
After mg ribbon is reacted completely with air, what is the reason to add some water and heat?
Vikentia [17]

The reason why some water and heat are added after Mg ribbon is reacted completely with air is to remove Mg3N2 as MgO.

Combustion reaction is a reaction in which a substance is completely burnt in oxygen. Magnesium ribbon can be converted to magnesium oxide by combustion in air.

The reaction is as follows; 2Mg(s) + O2 ----> 2MgO(s)

Since air contains nitrogen, Mg3N2 is also formed. Heat and water can be added to the reaction thereby converting magnesium nitride to magnesium oxide.

Learn more: brainly.com/question/11527546

3 0
2 years ago
A chemist prepares hydrogen fluoride by means of the following reaction:
natita [175]

Answer:

39.3%

Explanation:

CaF2 + H2SO4 --> CaSO4 + 2HF

We must first determine the limiting reactant, the limiting reactant is the reactant that yields the least number of moles of products. The question explicitly says that H2SO4 is in excess so CaF2 is the limiting reactant hence:

For CaF2;

Number of moles reacted= mass/molar mass

Molar mass of CaF2= 78.07 g/mol

Number of moles reacted= 11g/78.07 g/mol = 0.14 moles of Calcium flouride

Since 1 mole of calcium fluoride yields two moles of 2 moles hydrogen fluoride

0.14 moles of calcium fluoride will yield 0.14×2= 0.28 moles of hydrogen fluoride

Mass of hydrogen fluoride formed (theoretical yield) = number of moles× molar mass

Molar mass of hydrogen fluoride= 20.01 g/mol

Mass of HF= 0.28 moles × 20.01 g/mol= 5.6 g ( theoretical yield of HF)

Actual yield of HF was given in the question as 2.2g

% yield of HF= actual yield/ theoretical yield ×100

%yield of HF= 2.2/5.6 ×100

% yield of HF= 39.3%

4 0
3 years ago
HELPPPPP PLEASSEEEEE
timurjin [86]

Answer:

  • Dalton was first with the modeling
  • They soon followed so the answer is D: rutherford and bohr modeled their experiments
4 0
3 years ago
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