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Aleonysh [2.5K]
3 years ago
5

If we see a galaxy that is 100 light years from us and it appears red, that means that the galaxy is actually red in color

Physics
1 answer:
Sliva [168]3 years ago
5 0
Hello!

I believe the answer is false. Please let me know if you have any other questions. Have a bless day!

-Rose


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Why the efficiency of an engine cannot be 100%?
Marysya12 [62]
<span>No machine can operate at 100 percent efficiency because some of the energy input will always be used to overcome the force of gravity and the effects of friction and air resistance.</span>
6 0
3 years ago
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A powerful missile reaches a speed of 5 kilometers per second in 10 seconds after its launch. What is the average acceleration o
AveGali [126]

Average acceleration  =  (change in speed)  /  (time for the change)

The missile's change in speed is  (5,000 - 0)  =  5,000 m/s

Average acceleration  =  (5,000 m/s)  /  (10 sec)

                                 =      500 m/s²       (about  51 Gs)

Inconveniently, this isn't one of the choices on the list. Is there something wrong, either with the choices or with my solution ?

No. Relax. Everything is OK.

500 meters is the same thing as 0.5 kilometer.  So my answer can also be written as  0.5 km/s² .  That doesn't change anything, and it IS one of the listed choices.

The average acceleration is <em>0.5 km/sec²  (d)</em> .

4 0
3 years ago
Read 2 more answers
A playground merry-go-round of radius R = 1.40 m has a moment of inertia I = 265 kg · m2 and is rotating at 11.0 rev/min about a
Tom [10]

Answer:

The value of new value of angular speed of merry go round.\omega_{2} = 0.96 \frac{rad}{sec}

Explanation:

Given data

r = 1.4 m

Moment of inertia I_{1} = 265 kg - m^{2}

N_{1} = 11 RPM

\omega_{1} = \frac{2 \pi N}{60}

\omega_{1} = \frac{2 \pi (11)}{60}

\omega_{1} = 1.15 \frac{rad}{sec}

From conservation of momentum principal

I_{1} \omega_{1}  = I_{2} \omega_{2} ------- (1)

I_{2} = m r^{2} + 265

I_{2} = 27 (1.4)^{2} + 265

I_{2} = 317.92 \ kg m^{2}

Put all the values in equation  (1)

265 × 1.15 = 317.92 × \omega_{2}

\omega_{2} = 0.96 \frac{rad}{sec}

This is the value of new value of angular speed of merry go round.

6 0
3 years ago
Monochromatic light falls on two very narrow slits 0.048 mm apart. successive fringes on a screen 5.00 m away are 6.5 cm apart n
atroni [7]
In a double-slit interference experiment, the distance y of the maximum of order m from the center of the observed interference pattern on the screen is
y= \frac{m \lambda D}{d}
where D=5.00 m is the distance of the screen from the slits, and 
d=0.048 mm=0.048 \cdot 10^{-3}m is the distance between the two slits.
The fringes on the screen are 6.5 cm=0.065 m apart from each other, this means that the first maximum (m=1) is located at y=0.065 m from the center of the pattern.
Therefore, from the previous formula we can find the wavelength of the light:
\lambda =  \frac{yd}{mD}= \frac{(0.065 m)(0.048 \cdot 10^{-3}m)}{(1)(5.00 m)}=  6.24 \cdot 10^{-7}m

And from the relationship between frequency and wavelength, c=\lambda f, we can find the frequency of the light:
f= \frac{c}{\lambda}= \frac{3 \cdot 10^8 m/s}{6.24 \cdot 10^{-7}m}=4.81 \cdot 10^{14}Hz
4 0
3 years ago
How much time does it take for a car to accelerate from 3.44 m/s to 20.9 m/s if the average acceleration is 6.00 m/s^3
miv72 [106K]

Do you go to GA Connexus Academy??

4 0
4 years ago
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