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kobusy [5.1K]
4 years ago
12

HELP PLEASE BRAINLIEST 15 MIN!!!!

Physics
1 answer:
Elanso [62]4 years ago
4 0

Hi there! Hopefully this helps!

Answer: 24 units.

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Which statement is correct about the potential energy of a car moving down a ramp?
Paha777 [63]

Potential energy is highest when the car is released at the top of the ramp. The correct answer is option C

Potential energy is the energy possessed by a body when the body is at rest. Potential energy is at time called gravitational potential energy which as a product of mass of the body, acceleration due to gravity and the height attained by the body. That is,

P.E = mgh

When a car is moving down a ramp, the potential energy of the car can never remain the same except the car stop at a certain point.

Whenever a car is moving down a ramp, the potential energy of the car will be highest when the car is release at the top of the ramp. And lowest when the car reaches the bottom of the ramp.

The statement that is correct about the potential energy of a car moving down a ramp is:

Potential energy is highest when the car is released at the top of the ramp.

Therefore, the correct answer is option C

Learn more here: brainly.com/question/17400615

8 0
3 years ago
Consider the reaction.
Free_Kalibri [48]

2.1 x 102

Is the correct solution for this problem

5 0
3 years ago
Read 2 more answers
Given two vectors A= 4.00i + 7.00jand B= 5.00i-2.00ja.Find the magnitude of each vector.b.Find the vector differenceC= A –B, giv
Tpy6a [65]

Answer:

444.99

Explanation:

8 0
4 years ago
A ballet dancer spins with 2.4 rev/s with her arms outstretched,when the moment of inertia about axis of rotation is 1 .With her
kow [346]

Correct question is;

A ballet dancer spins with 2.4 rev/s with her arms outstretched,when the moment of inertia about axis of rotation is I. With her arms folded,the moment of inertia about the same axis becomes 0.6I about the same axis. Calculate the new rate of spin.

Answer:

4 rev/s

Explanation:

We are given;

Initial Angular velocity; ω_i = 2.4 rev/s

Initial moment of inertia; I_i = I

Final moment of inertia; I_f = 0.6I

From conservation of angular momentum, we have;

I_i × ω_i = I_f × ω_f

Where ω_f is the new rate of spin.

Thus, let's make it the subject to get;

ω_f = (I_i × ω_i/I_f)

Plugging in relevant values, we have;

ω_f = (I × 2.4/0.6I)

I will cancel out to give;

ω_f = 2.4/0.6

ω_f = 4 rev/s

5 0
3 years ago
A soccer ball is kicked at an angle of 30° to the horizontal with an initial velocity of 16 m/s. How high does the soccer ball g
Ugo [173]
Vertical component of velocity = 16sin(30°) = 8m/s

at the highest point of flight, the velocity of the ball is 0 (that moment when it stops before starting to fall) so:
v^2=u^2+2as<u />
0^2=8^2+(2\times-9.81\times s)
s= \frac{0^2-8^2}{2\times-9.81}<u />
s=3.26m

So rounding up gives option B. (3.3m)

6 0
4 years ago
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