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Nostrana [21]
3 years ago
15

We can calculate the force that the atmospheric pressure produces on a surface. Consider a living room that has a 4.0m×5.0m floo

r and a ceiling 3.0m high. What is the total force on the floor due to the air above the surface if the air pressure is 1.00 atm?
Physics
1 answer:
qaws [65]3 years ago
4 0

Answer:

Force, F=2.02\times 10^6\ N

Explanation:

It is given that,

Length of the room, l = 4 m

breadth of the room, b = 5 m

Height of the room, h = 3 m

Atmospheric pressure, P=1\ atm=101325\ Pa

We know that the force acting per unit area is called pressure exerted. Its formula is given by :

P=\dfrac{F}{A}

F=P\times l\times b

F=101325\times 4\times 5

F=2.02\times 10^6\ N

So, the total force on the floor due to the air above the surface is 2.02\times 10^6\ N. Hence, this is the required solution.

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A seagull flying horizontally over the ocean at a constant speed of 2.60 m/s carries a small fish in its mouth. It accidentally
Ivenika [448]

(a) +2.60 m/s

The motion of the fish dropped by the seagul is a projectile motion, which consists of two independent motions:

- a horizontal uniform motion, at constant speed

- a vertical motion, at constant acceleration (acceleration of gravity, g=-9.8 m/s^2, downward)

In this part we are only interested in the horizontal motion. As we said the horizontal component of the fish's velocity does not change, therefore its value when the fish reaches the ocean is equal to its initial value, which is the speed at which the seagull was flying (because it was flying horizontally):

v_x = +2.60 m/s

(b) -17.2 m/s

The vertical component of the fish's velocity instead follows the equation:

v_y = u_y +gt

where

u_y = 0 is the initial vertical velocity, which is zero

g=-9.8 m/s^2 is the acceleration of gravity

t is the time

Since the fish reaches the ocean at t = 1.75 s, we can substitute this time into the formula to find the final vertical velocity:

v_y = 0+(-9.8)(1.75)=-17.2 m/s

where the negative sign indicates the direction (downward).

(c)

The horizontal component of the fish's velocity would increase

The vertical component of the fish's velocity would stay the same.

As we said from part (a) and (b):

- The horizontal component of the fish's velocity is constant during the motion and it is equal to the initial velocity of the seagull -> so if the seagull's initial speed increases, the horizontal velocity of the fish will increase too

- The vertical component of the fish's velocity does not depend on the original speed of the seagull, therefore it is not affected.

4 0
3 years ago
A merry-go-round with a a radius of R = 1.99 m and moment of inertia I = 194 kg-m2 is spinning with an initial angular speed of
Aleksandr [31]

Answer:

Part 1)

L_1 = 185.2 kg m^2/s^2

Part 2)

L_2 = 663.07 kg m^2/s^2

Part 3)

L = 663.07 kg m^2/s^2

Part 4)

\omega = 1.83 rad/s

Part 5)

F_c = 453.6 N

Explanation:

Part a)

Initial angular momentum of the merry go round is given as

L_1 = I \omega

here we know that

I = 194 kg m^2

\omega = 1.47 rad/s^2

now we have

L_1 = 194 \times 1.47

L_1 = 185.2 kg m^2/s^2

Part b)

Angular momentum of the person is given as

L = mvR

so we have

m = 68 kg

v = 4.9 m/s

R = 1.99 m

so we have

L_2 = (68)(4.9)(1.99)

L_2 = 663.07 kg m^2/s^2

Part 3)

Angular momentum of the person is always constant with respect to the axis of disc

so it is given as

L = 663.07 kg m^2/s^2

Part 4)

By angular momentum conservation of the system we will have

L_1 + L_2 = (I_1 + I_2)\omega

185.2 + 663.07 = (194 + 68(1.99^2))\omega

848.27 = 463.28 \omega

\omega = 1.83 rad/s

Part 5)

Force required to hold the person is centripetal force which act towards the center

so we will have

F_c = m\omega^2 R

F_c = 68(1.83^2)(1.99)

F_c = 453.6 N

3 0
3 years ago
If you apply 3 times the force for 4 times the distance, how much does your work increase?
masha68 [24]
12 increase When force is multiplied by the distance over which it is applied, that amount is given ... force * distance = work
4 0
3 years ago
What's an interesting fact about Aristotle?
gladu [14]

Answer:

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Interesting Aristotle Facts: 1-5

Aristotle was born somewhere around 384 BCE. ...

His father was Nicomachus. ...

Nicomachus died when Aristotle was a young boy. ...

After the death of Nicomachus, Proxenus – husband of Aristotle's sister Arimneste, became the guardian of young Aristotle.

8 0
3 years ago
As global population ______
Sedbober [7]

Answer:

As global population a.) <u>increases</u> food production must a.) <u>increase</u>.

Example:

More people means more food must be produced.

6 0
3 years ago
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