Answer:
We can use  2 g H = v2^2 - v1^2    or 
v2^2 = 2 g H + v1^2
Since 88 ft/sec = 60mph   we have 30 mph = 44 ft/sec
The object will return with the same speed that it had initially so the object
starts out with a downward speed of 44 ft/sec
Then v2^2 = 2 * 32 ft/sec^2 * 160 ft + 44 (ft/sec)^2
v2^2 = (2 * 32 * 160 + 44^2) ft^2 / sec^2 = 12180 ft^2/sec^2
v2 = 110 ft/sec
 
        
             
        
        
        
A speed cause it would slow down meeting eachother
        
             
        
        
        
Req = 30.0Ω. 
When two or more resistors are in series, the intensity of current that passes through each of them is the same. Therefore, if you notice, you can observe that the three previous series resistors are equivalent to a single resistance whose value is the sum of each one.
Req = R1 + R2 + R3 = 10.0Ω + 10.0Ω + 10.0Ω = 30.0Ω
 
        
                    
             
        
        
        
Gravitational force decreases with increasing distance. So it decreases!