This would be louder sound. Higher pitch would be represented by a more compressed wave that oscillates more times over a shorter period. Higher amplitude represents higher sound because the wave oscillates at the same speed, yet higher.
Hope this helped, and have a nice day!
I dont see a question 38 for the second one
You'll be using the equation f = m a, or force = mass x acceleration
First, you have to find the acceleration. The acceleration needed is the average acceleration over the 15 seconds is accelerated. So, you take the change in speed (25m/s - 15m/s) to get a change of 10m/s.
The average acceleration (acceleration per second) is found by dividing total acceleration by the time it took. So, it's 10 / 15, which equals .6. This is a, your acceleration
Now just plug it into the equation F = m a, because it already gives you the mass of the car
F = 550 x .6
Solve that to get F = 366.6. F is measured in Newtons (N), so your answer is 366.6N
<span>To determine the magnitude and the direction of the resultant force, we assume that the forces are in XY coordinate plane and the angles that are given are from the x axis.
</span>
<span>The 110 N force is said to act at 90 deg which means it is along the Y axis. The </span><span>55 N force is said to act at 0 deg which means it is along the X axis. so, a right angle is made by the two forces. Thus, the
</span>
<span>X component of the resultant force = 55 N </span>
<span>Y component of the resultant force = 110 N </span>
<span>Magnitude of the resultant force would be calculated as follows:
R = √(Fx^2 + Fy^2)
R = √(55^2 + 110^2) </span>
<span>R = √(15125) </span>
<span>R = 123 N </span>
<span>The resultant force would have its terminal side in the x-axis. We calculate angle θ as follows:
</span>
<span>tan θ = Fy/Fx </span>
<span>tan θ = 110 N /55 N = 2
</span>θ = arctan(2)
θ <span>= 63.4 degrees
</span>Therefore, the m<span>agnitude of the resultant force is 123 N and the direction would be at an angle of 63.4 degrees.</span>
