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spayn [35]
3 years ago
12

Hey anyone that responds I will thank and turn vrai lies y question

Physics
2 answers:
Natali [406]3 years ago
4 0

Does this count as a response? Or do you want me to answer a question?

ExtremeBDS [4]3 years ago
4 0

Boo to you good person pl0s thank me

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A 500 kg sports car accelerates uniformly from rest reaching a speed of 30 m/s in 6 seconds .Find the distance travelled by the
Dimas [21]

Answer:

the distance traveled by the sports car is 90 m

Explanation:

Given;

mass of the sports car, m = 500 kg

initial velocity of the sports car, u = 0

final velocity of the sport car, v = 30 m/s

time of motion of the car, t = 6 s

The distance traveled by the sports car is calculated as;

s = (\frac{u+v}{2} )t\\\\s = (\frac{0+30}{2} ) \times 6\\\\s = 15 \times 6\\\\s = 90 \ m

Therefore, the distance traveled by the sports car is 90 m

6 0
3 years ago
Una cuerda es puesta a vibrar 400 veces en 4 segundos Cual es la frecuencia del sonido emitido?
Readme [11.4K]

n = number of vibrations set in the string = 400 vibrations

t = total time taken for "n" vibrations set in the string = 4 second

f = frequency of the sound emitted due to vibrations set in the string


frequency of the sound emitted due to vibrations set in the string is given as

f = n/t

inserting the above values in the above formula

f = 400/4

f = 100 Hz

hence the frequency of sound comes out to be 100 Hz

4 0
3 years ago
A soccer player is running upfield at 10 m/s and comes to a stop in 3 seconds facing the same direction. What is his acceleratio
I am Lyosha [343]
His acceleration would be 3.34 m/s 
5 0
3 years ago
In my trigonometry class, we were assigned a problem on Angular and Linear Velocity.
Rzqust [24]

1) 0.0011 rad/s

2) 7667 m/s

Explanation:

1)

The angular velocity of an object in circular motion is equal to the rate of change of its angular position. Mathematically:

\omega=\frac{\theta}{t}

where

\theta is the angular displacement of the object

t is the time elapsed

\omega is the angular velocity

In this problem, the Hubble telescope completes an entire orbit in 95 minutes. The angle covered in one entire orbit is

\theta=2\pi rad

And the time taken is

t=95 min \cdot 60 =5700 s

Therefore, the angular velocity of the telescope is

\omega=\frac{2\pi}{5700}=0.0011 rad/s

2)

For an object in circular motion, the relationship between angular velocity and linear velocity is given by the equation

v=\omega r

where

v is the linear velocity

\omega is the angular velocity

r is the radius of the circular orbit

In this problem:

\omega=0.0011 rad/s is the angular velocity of the Hubble telescope

The telescope is at an altitude of

h = 600 km

over the Earth's surface, which has a radius of

R = 6370 km

So the actual radius of the Hubble's orbit is

r=R+h=6370+600=6970 km = 6.97\cdot 10^6 m

Therefore, the linear velocity of the telescope is:

v=\omega r=(0.0011)(6.97\cdot 10^6)=7667 m/s

4 0
3 years ago
Lee pushes horizontally with a force of 75 n on a 36 kg mass for 10 m across a floor. calculate the amount of work lee did. answ
svlad2 [7]
To find work, you use the equation: W = Force X Distance X Cos (0 degrees)
Following the Law of Conservation of Energy, energy cannot be destroyed nor created.

So you would do 75 N x 10m x Cos (0 degrees)= 750 J
8 0
3 years ago
Read 2 more answers
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