Answer:
the distance traveled by the sports car is 90 m
Explanation:
Given;
mass of the sports car, m = 500 kg
initial velocity of the sports car, u = 0
final velocity of the sport car, v = 30 m/s
time of motion of the car, t = 6 s
The distance traveled by the sports car is calculated as;

Therefore, the distance traveled by the sports car is 90 m
n = number of vibrations set in the string = 400 vibrations
t = total time taken for "n" vibrations set in the string = 4 second
f = frequency of the sound emitted due to vibrations set in the string
frequency of the sound emitted due to vibrations set in the string is given as
f = n/t
inserting the above values in the above formula
f = 400/4
f = 100 Hz
hence the frequency of sound comes out to be 100 Hz
1) 0.0011 rad/s
2) 7667 m/s
Explanation:
1)
The angular velocity of an object in circular motion is equal to the rate of change of its angular position. Mathematically:

where
is the angular displacement of the object
t is the time elapsed
is the angular velocity
In this problem, the Hubble telescope completes an entire orbit in 95 minutes. The angle covered in one entire orbit is
rad
And the time taken is

Therefore, the angular velocity of the telescope is

2)
For an object in circular motion, the relationship between angular velocity and linear velocity is given by the equation

where
v is the linear velocity
is the angular velocity
r is the radius of the circular orbit
In this problem:
is the angular velocity of the Hubble telescope
The telescope is at an altitude of
h = 600 km
over the Earth's surface, which has a radius of
R = 6370 km
So the actual radius of the Hubble's orbit is

Therefore, the linear velocity of the telescope is:

To find work, you use the equation: W = Force X Distance X Cos (0 degrees)
Following the Law of Conservation of Energy, energy cannot be destroyed nor created.
So you would do 75 N x 10m x Cos (0 degrees)= 750 J