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2 years ago

Haley's swim team hosted a home meet and needed volunteers. How did she reveal to her coach that she is not a team player?

Physics

2 answers:

Mrrafil [7]2 years ago

6 0

C: Left Meet after her events were over

vladimir2022 [97]2 years ago

3 0

It is C, Left the Meet after her events were over

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(d) If η = 40% and TH = 427°C, what is TC, in °C?

Brrunno [24]

Answer:

$T_C=256.2^{\circ}C$

Explanation:

Given that,

Efficiency of heat engine, $\eta=40\%=0.4$

Temperature of hot source, $T_H=427^{\circ}C$

We need to find the temperature of cold sink i.e. $T_C$ . The efficiency of heat engine is given by :

$\eta=1-\dfrac{T_C}{T_H}$

$T_C=(1-\eta)T_H$

$T_C=(1-0.4)\times 427$

$T_C=256.2^{\circ}C$

So, the temperature of the cold sink is 256.2°C. Hence, this is the required solution.

3 0

3 years ago

Why is deforestation a serious global environment problem

julia-pushkina [17]

Answer:

we all know that deforestation is when tress are cut down but this may cause cardio dioxide to go up into the atmosphere and this may cause the rise in sea level and temperates tend to fluctuate

Explanation:

I'm just that smart yah dig

5 0

2 years ago

Amadeo the Archer is practicing his archery skills. He shoots both arrows into a field. His first arrow (arrow A) is embedded ha

attashe74 [19]

Answer:

The arrow with greater impart is Arrow B

The both arrows will feel the same impulse

Explanation:

1. Arrow B since $KE= W = F * d$ it used more force to stop itself in a shorter distance.

2. They should feel the same impulse since the both had the same momentum $m * v= F * t$

4 0

2 years ago

Josh tests an unknown liquid substance using litmus paper. When he compared the used litmus paper to a pH scale, the color match

Hunter-Best [27]

Answer:

acid

Explanation:

because ph below 7 is acid

8 0

2 years ago

You push on a cart (18.0kg) at a 30 degree below horizontal angle. The coefficient of kinetic friction between the chair and the

podryga [215]

Given that force is applied at an angle of 30 degree below the horizontal

So let say force applied if F

now its two components are given as

$F_x = Fcos30$

$F_y = Fsin30$

Now the normal force on the block is given as

$N = Fsin30 + mg$

$N = 0.5F + (18\times 9.8)$

$N = 0.5F + 176.4$

now the friction force on the cart is given as

$F_f = \mu N$

$F_f = 0.625(0.5F + 176.4)$

$F_f = 110.25 + 0.3125F$

now if cart moves with constant speed then net force on cart must be zero

so now we have

$F_f + F_x = 0$

$Fcos30 - (110.25 + 0.3125F) = 0$

$0.866F - 0.3125F = 110.25$

$F = 199.2 N$

so the force must be 199.2 N

8 0

2 years ago