It's "C" a sample of dust particles at 0 Pascals
Explanation:
Using stratified random sampling, researchers must identify characteristics, divide the population into strata, and proportionally choose individuals for the representative sample. ... For example, individuals who are too busy to participate will be under-represented in the representative sample.
Answer:
0.200 m K3PO3
Explanation:
Let us remember that the freezing point depression is obtained from the formula;
ΔTf = Kf m i
Where;
Kf = freezing point constant
m = molality
i = Van't Hoff factor
The Van't Hoff factor has to do with the number of particles in solution. Let us consider the Van't Hoff factor for each specie.
0.200 m HOCH2CH2OH - 1
0.200 m Ba(NO3)2 - 3
0.200 m K3PO3 - 4
0.200 m Ca(CIO4)2 - 3
Hence, 0.200 m K3PO3 has the greatest van't Hoff factor and consequently the greatest freezing point depression.
Answer: The mass of 
and 
produced are 336.6 g and 183.6 g respectively.
Explanation:
The combustion reaction between propane and oxygen leads to formation of carbon dioxide and water.
Law of Conservation of mass states that the mass will remain constant for a balanced equation. This is carried out when the total number of atoms on reactant side is same as the total number of atoms on the product side. Thus the equation must be balanced.
a) 1 mol of propane produces = 3 moles of
Thus 2.55 mol of propane produces = ![\frac{3}{1}\times 2.55=7.65 moles of [tex]CO_2](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B1%7D%5Ctimes%202.55%3D7.65%20moles%20of%20%5Btex%5DCO_2)
mass of 
b) 1 mol of propane produces = 4 moles of
Thus 2.55 mol of propane produces = ![\frac{4}{1}\times 2.55=10.2 moles of [tex]H_2O](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B1%7D%5Ctimes%202.55%3D10.2%20moles%20of%20%5Btex%5DH_2O)
mass of 
The mass of and produced are 336.6 g and 183.6 g respectively.
