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sasho [114]
3 years ago
10

A 5.0 kg dog sits on the floor of an elevator that is accelerating downward at 1.20 m/s^2 .?

Physics
1 answer:
nalin [4]3 years ago
5 0
A)
Upward force = Normal Force
Downward force = weight
Resultant force = ma

Resultant = Weight - Normal
1.2 x 5 = 1.2 x 9.81 - Fn
Fn = 5.77 N

B) 
The reactant force is equal to the force exerted by the dog, just in the opposite direction. Thus, the dog's force is also 5.77 N.
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v₁f = 0.5714 m/s   (→)

v₂f = 2.5714 m/s   (→)

e = 1  

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Explanation:

m₁ = m

m₂ = 6m₁ = 6m

v₁i = 4 m/s

v₂i = 2 m/s

v₁f = ((m₁ – m₂) / (m₁ + m₂)) v₁i +  ((2m₂) / (m₁ + m₂)) v₂i

v₁f = ((m – 6m) / (m + 6m)) * (4) +  ((2*6m) / (m + 6m)) * (2)  

v₁f = 0.5714 m/s   (→)

v₂f = ((2m₁) / (m₁ + m₂)) v₁i +  ((m₂ – m₁) / (m₁ + m₂)) v₂i

v₂f = ((2m) / (m + 6m)) * (4) + ((6m -m) / (m + 6m)) * (2)

v₂f = 2.5714 m/s   (→)

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It was a perfectly elastic collision.

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