Question

(a) Calculate the electric field strength near a 10.0 cm diameter conducting sphere that has 1.00 C of excess charge on it. (b) What is unreasonable about this result? (c) Which assumptions are responsible?

Answer 1

Electric field strength near the surface of sphere is given by

$E = \frac{kQ}{r^2}$

Now we have

Q = 1 C

R = 5 cm

now electric field is given by

$E = \frac{9*10^9 * 1}{0.05^2}$

$E = 3.6 * 10^{12} N/C$

Part B)

Since charge on the sphere is very large to electric field near its surface is too high. So this is reasonable result near it.

Part c)

As per our assumption the charge is uniformly distributed on the surface and there is no effect of surrounding charge or surrounding electric field.