The pressure drop of air in the bed is 14.5 kPa.
<u>Explanation:</u>
To calculate Re:

From the tables air property

Ideal gas law is used to calculate the density:
ρ = 
ρ = 1.97 Kg / 
ρ = 
R =
= 8.2 ×
/ 28.97×
R = 2.83 ×
atm / K Kg
q is expressed in the unit m/s
q = 1.24 m/s
Re =
Re = 2278
The Ergun equation is used when Re > 10,


= 4089.748 Pa/m
ΔP = 4089.748 × 3.66
ΔP = 14.5 kPa
Answer: nutrients
Explanation: to help the cells have energy
Answer:
cross-weight is used to tighten it up.
Explanation:
and yes this is important because Cross-weight percentage compares the diagonal weight totals to the car's total weight.
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Answer:
of 5 lb/ft and a concentrated service live load at midspan. .... length = 12 feet) to support a uniformly distributed load. Taking ... w 7..'{ 'f.- ~ s-·. 344 ft-kip. Fy : s-o ks I. 299 ft-kip. Li.. ::::- I 2.. }-t-. 150 ft-kip ..... The concrete and reinforcing steel properties are ... Neglecting beam self-weight . and based only on the ...... JI : Lf, 2. l.. ;VI.
Explanation:
Answer:
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