Answer : The pH of 0.001 M is, 2.69 and the pH after mixing the solution is, 3.30.
Explanation :
First we have to calculate the concentration of hydrogen ion.
The balanced dissociation reaction will be,
The concentration of = x = 0.001 M
The concentration of ion = 2x = 2 × 0.001 M = 0.002 M
The concentration of = x = 0.001 M
Now we have to calculate the pH of 0.001 M .
Now we have to calculate the molarity after mixing the solution.
where,
= molarity of solution = 0.001 M
= volume of solution = 250 ml
= molarity of after mixing = ?
= volume of after mixing = 250 + 750 = 1000 ml
Now put all the given values in the above formula, we get the molarity after mixing the solution.
The concentration of ion =
Now we have to calculate the pH after mixing the solution.
Therefore, the pH of 0.001 M is, 2.69 and the pH after mixing the solution is, 3.30.