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ser-zykov [4K]
4 years ago
12

Where might you find a temperature of 2 kelvin?

Chemistry
1 answer:
lyudmila [28]4 years ago
7 0
100°C is 273 kelvins.

1°C is 2.73 kelvins.

I guess the closest would be north pole
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You are well acquainted with the negative effects of the greenhouse effect, but the fact remains that without it, Earth would be
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Greenhouse effect is the natural phenomenon which makes the Earth's atmosphere favorable for any form of life. As the sun's rays radiates into the atmosphere, some are deflected while some are absorbed. The Earth reflects this back, causing the heat to be trapped. At night, this keeps the Earth warm enough. Without the greenhouse effect, nights would be too cold and days would be too hot that life cannot be sustained.
3 0
4 years ago
BALANCING EQUATION<br> XC12(aq) + AgNO3(aq)<br> X(NO3)2(aq) +AgCl(s)
slava [35]
Answer:


XCl2(aq) + 2 AgNO3(aq) = 2 AgCl(s) + X(NO3)2(aq)
8 0
3 years ago
Chlorine-36 does what
Lelu [443]

Answer:

Chlorine-36 undergoes β-decay.

Explanation:

Cl-36 is radioactive. It emits an electron ( a β-particle) to become more stable and forms Ar-36.

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3 0
4 years ago
The [H3O+] of a solution with pH = 2.0 is.
Licemer1 [7]

Answer:

[H_{3}O^{+} ] = 10^{-2} mol/ L

Explanation:

Measure of  [H₃O⁺] , i.e hydrogen ion concentration, indicates the acidity of the solution. The greater the concentration, the greater is the acidity.  [H₃O⁺], this quantity can range from 10⁻¹ to 10⁻¹⁴ at ambient temperature(298K). This range is always temperature dependent.

Measure of acidity of a solution is expressed more conveniently using the notation of pH.

pH = - log_{10}[H_{3}O^{+} ]

Using the above formula

[H_{3}O^{+} ] = 10^{-(pH)}

[H_{3}O^{+} ] = 10^{-2} mol/ L

8 0
3 years ago
You have competed an extraction procedure on a mixture of compounds known to contain Lauric acid ( it to get necessary physical
marin [14]

Answer:

3.5 mL

Explanation:

Let us represent lauric acid with the symbol LaCOOH and the anion as LaCOO-. The reaction between the anion and H2SO4 is;

LaCOO-(aq) +  H2SO4(aq) ----->  LaCOOH(aq) + HSO4-(aq)

Number of moles of LaCOO- = 2.75 g/200 g/mol = 0.014 moles

Since the mole ratio of the reaction is 1:1, then the amount of H2SO4 required is also 0.014 moles

Then;

n = CV

n = number of moles

C= concentration

V = volume

V = n/C

V = 0.014 moles/4.0 M

V= 3.5 * 10^-3 L

V = 3.5 mL

5 0
3 years ago
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