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Lisa [10]
3 years ago
10

How does the behavior of a high-energy particle compare to a low-energy particle?

Chemistry
1 answer:
irina1246 [14]3 years ago
5 0

Answer:

The problem of energy exchange between waves and particles, which leads to energization of the latter, in an unstable plasma typical of the radiation belts. The ongoing Van Allen Probes space mission brought this problem among the most discussed in space physics. A free energy which is present in an unstable plasma provides the indispensable condition for energy transfer from lower energy particles to higher-energy particles via resonant wave-particle interaction. This process is studied in detail by the example of electron interactions with whistler mode wave packets originated from lightning-induced emission. We emphasize that in an unstable plasma, the energy source for electron energization is the energy of other particles, rather than the wave energy as is often assumed. The way by which the energy is transferred from lower energy to higher-energy particles includes two processes that operate concurrently, in the same space-time domain, or sequentially, in different space-time domains, in which a given wave packet is located. In the first process, one group of resonant particles gives the energy to the wave. The second process consists in wave absorption by another group of resonant particles, whose energy therefore increases. We argue that this mechanism represents an efficient means of electron energization in the radiation belts.

Explanation:

Fun facts:

In the process of energy transfer between two groups of particles both processes operate simultaneously, and if the lower energy part of plasma distribution gives energy to the wave while the higher‐energy part absorbs the wave enrgy, then the wave‐mediated energy transfer from lower energy particles to higher‐energy ...

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Consider the reaction 2 NO + O2 → 2 NO2
Sonbull [250]

Answer:

(a) Rate at which NO_2 is formed is 0.050 M/s

(b) Rate at which O_2 is consumed is 0.0250 M/s.

Explanation:

The given reaction is:-

2NO+O_2\rightarrow 2NO_2

The expression for rate can be written as:-

-\frac{1}{2}\frac{d[NO]}{dt}=-\frac{d[O_2]}{dt}=\frac{1}{2}\frac{d[NO_2]}{dt}

Given that:- \frac{d[NO]}{dt}=-0.050\ M/s (Negative sign shows consumption)

-\frac{1}{2}\frac{d[NO]}{dt}=\frac{1}{2}\frac{d[NO_2]}{dt}

-\frac{d[NO]}{dt}=\frac{d[NO_2]}{dt}

-(-0.050\ M/s)=\frac{d[NO_2]}{dt}

\frac{d[NO_2]}{dt}=0.050\ M/s

(a) Rate at which NO_2 is formed is 0.050 M/s

-\frac{1}{2}\frac{d[NO]}{dt}=-\frac{d[O_2]}{dt}

-\frac{1}{2}\times -0.050\ M/s=-\frac{d[O_2]}{dt}

\frac{d[O_2]}{dt}=0.0250\ M/s

(b) Rate at which O_2 is consumed is 0.0250 M/s.

5 0
3 years ago
How much in mg/l is 0,327 meq/l chloride? I highly appreciate and love to know how you can calculate that.
evablogger [386]
0.00923728813559322 is the answer (:
6 0
3 years ago
How many moles of pcl3 contain 3.68 × 1025 chlorine atoms?
disa [49]
To answer the question above, we take note first that every mole of PCl₃ contains 3 atoms of Cl. First, we divide the given number by 3.
                                   3.68 x 10²⁵ / 3 = 1.227 x 10²⁵ 
Then, we divide the answer by the Avogadro's number which is equal to 6.022 x 10²³. That is,
                                    1.227 x 10²⁵ / (6.022 x 10²³) = 20.37
Thus, there are 20.37 mol of PCl₃. 
4 0
3 years ago
Read 2 more answers
Please help, timed test, will give brainliest
OlgaM077 [116]

Answer:

The answer to your question is letter B

Explanation:

A.)                     2 AgCl + Na2S ⟶ 2 Ag2S + 2 NaCl

                Reactants           Elements              Products

                      2                         Ag                         4

                      2                          Cl                          2

                      2                          Na                         2

                      1                            S                           2

This reaction is unbalanced

B.)                       2 AgCl + Na2S ⟶ Ag2S + 2 NaCl

                Reactants           Elements              Products

                      2                         Ag                         2

                      2                          Cl                          2

                      2                          Na                         2

                      1                            S                           1

This reaction is balanced

C.)                         AgCl + Na2S ⟶ 2 Ag2S + 2 NaCl

                Reactants           Elements              Products

                      1                         Ag                         4

                      1                          Cl                          2

                      2                          Na                         2

                      1                            S                           2

This reaction is unbalanced

D.)                2 AgCl + 2 Na2S ⟶ Ag2S + NaCl

                Reactants           Elements              Products

                      2                         Ag                         4

                      2                          Cl                          1

                      4                          Na                         1

                      2                            S                          1

This reaction is unbalanced

4 0
3 years ago
Can someone please help me calculate the pH and pOH of these?????
FinnZ [79.3K]

a. pH=5, pOH=9

b. pH=6.4771, pOH=7.5229

c. pH=1.6021, pOH=12.3979

d. pH=11.8751, pOH=2.1249

e. pH=13.9208, pOH=0.0792

4 0
3 years ago
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