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o-na [289]
4 years ago
11

A clock has radius of 0.5m. The outermost point on its minute hand travels along the edge. What is its tangential speed?

Physics
1 answer:
Andreas93 [3]4 years ago
6 0
The angular speed of the minute hand is the ratio between the angle covered and the time taken. The angle covered by the minute hand is 2 \pi, while the time needed is t=60 min= 3600 s, so the angular speed is
\omega =  \frac{2 \pi}{3600 s}=0.0017 rad/s

And the tangential speed is given by
v=\omega r=(0.0017 rad/s)(0.5 m)=8.72 \cdot 10^{-4} m/s
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