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Kobotan [32]
3 years ago
8

Rank the following metals in order of increasing activity: Pb, Mg, Cu, and Ag

Chemistry
1 answer:
Goryan [66]3 years ago
8 0
They would be the following

Mg, Pb, Cu, Ag
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What is the work required for the separation of air (21-mol-% oxygen and 79-mol-% nitrogen) at 25°C and 1 bar in a steady-flow p
Ronch [10]

Answer:

4oo

Explanation:

it

4 0
3 years ago
Enter a balanced equation for the reaction between aqueous lead (II) nitrite and aqueous lithium chloride to form solid lead (II
Dominik [7]

Answer:

Pb(NO₂)₂(aq) + 2 LiCl(aq) ⇒ PbCl₂(s) + 2 LiNO₂(aq)

Explanation:

Let's consider the reaction between aqueous lead (II) nitrite and aqueous lithium chloride to form solid lead (II) chloride and aqueous lithium nitrite.

Pb(NO₂)₂(aq) + LiCl(aq) ⇒ PbCl₂(s) + LiNO₂(aq)

This is a double displacement reaction. We will start balancing Cl by multiplying LiCl by 2.

Pb(NO₂)₂(aq) + 2 LiCl(aq) ⇒ PbCl₂(s) + LiNO₂(aq)

Now, we have to balance Li by multiplying LiNO₂ by 2.

Pb(NO₂)₂(aq) + 2 LiCl(aq) ⇒ PbCl₂(s) + 2 LiNO₂(aq)

The equation is now balanced.

4 0
3 years ago
A chemical reaction can theoretically produce 1375.5 grams of product , but in actuality 112.9 grams are product . Which is the
zalisa [80]

Answer:

8.20 % → Percent yield reaction

Explanation:

To find the percent yield of reaction we apply this:

(Produced yield / Theoretical yield) . 100 = %

Produced yield = 112.9 g

Theoretical yield = 1375.5 g

We replace → (112.9g / 1375.5 g) . 100

8.20 % → Percent yield reaction

3 0
3 years ago
what is the molar mass of a gaseous flouride of sulfur containing 70.4% F and having a density of approximately 4.5g/L at 20 deg
zlopas [31]

Answer:

The molar mass is 180.2 g/mol

Explanation:

<u>Step 1:</u> Data given

% of F = 70.4 %

Density = 4.5 g/L

Temperature = 20 °C

Pressure = 1 atm

<u>Step 2:</u> Calculate the number of moles

PV = nRT

 ⇒ with P = the pressure = 1.00 atm

⇒ with V = the volume = Assume this is 1L

⇒ with n = the number of moles = TO BE DETERMINED

⇒ R = the gas constant = 0.08206 L*atm/K*mol

⇒ T = the temperature : 20°C = 293 Kelvin

1 atm*1L= n(0.08206 L-atm/mol-K)*(293 K)

n = 0.04159 moles

<u>Step 3</u>: Calculate molar mass

Molar mass = Mass / moles

4.5 grams / 0.04159 moles = 108.2 g/mol

<u>Step 4:</u> Calculate moles of F

Moles = Mass / molar mass

Moles F = 70.4 g / 19 g/mol

Moles F =  3.70 moles

Moles S = 29.6g / 32.07 g/mol

Moles S = 0.923 moles S

<u>Step 5:</u> Divide by the smallest amount of moles

F = 3.70 / 0.923 = 4

S = 0.923 / 0.923 = 1

The empirical formula is SF4

The molar mass of SF4 = 32.07 + 4*19 = 108.07 g/mol

This means the empirical formula is the same as the molecular formula SF4

The molar mass is 180.2 g/mol

4 0
3 years ago
6. The gas in a steel cylinder is at 55 °C and a pressure of 965 mmHg. What would be the temperature,
ohaa [14]

Answer:

91.4°C

Explanation:

Gay - Lussac Law => T ∝ P => T = kP => k = T/P with volume (V) and mass (n) constant.

For two different Temperature (T)-Pressure (P) conditions

k₁ = k₂ => T₁/P₁ = T₂/P₂ => T₂ = T₁(P₂/P₁)

T₁ = 55°C = (55 + 273)K = 328K      

P₁ = 965 mmHg

T₂ =  ?

P₂ = 850 mmHg

T₂ = T₁(P₂/P₁) = 328K(850 mmHg/965 mmHg) = 364K = (364 - 273)°C = 91.4°C

6 0
2 years ago
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