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3 years ago

What is the kinetic energy of a 1500 kg object moving at a velocity of 10 m/s?

1 answer:

4 0

The Kinetic Energy Formula is as follows: KE = mass x velocity^2 /2

Plug in the correct numbers into the variables!

KE = 1500 kg x 10 m/s ^2 / 2

Square the 10 m/s!

KE = 1500 kg x 100 m/s / 2

Multiply!

KE = 150,000 / 2

Divide!

KE = 75,000 Newton-meters or Joules!

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Imagine your teacher asks you to design an experiment where you test the effect of temperature on the growth of a plant. You hav

Dmitry_Shevchenko [17]

Answer:

The correct answer will be-

1. Dependent variable- The growth of plant in the form of height

2. Independent variable- different temperature

3. Constant variable- The amount of water, amount of sunlight, type of soil.

Explanation:

A Scientific experiment must include three types of variables which are: The independent, dependent and the constant variable.

1. Independent variable- The variable which can be modified or changed either on its own or manually. The variable directly influences the variable to be studied. In the given condition, the independent variable is the different temperature provided to the plants.

2. Dependent variable- The variable which is being studied in the experiment and directly influenced by the independent variable is the growth of the plant which is measured in the form of height.

3. Constant variable- The variable which is kept constant throughout the experiment and remains the same which could be the amount of water amount of sunlight and type of soil.

4 0

3 years ago

Harry Potter is chasing his nemesis Draco Malfoy during a quidditch match. Initially, Harry is 35m behind Draco, who has just sp

Sophie [7]

Answer:

the acceleration of harry is equal to 66.126 m/s²

Explanation:

given,

harry is 35 m behind Draco

speed of Draco = 40 m/s

original speed of harry = 50 m/s

acceleration = ?

time taken by the Draco

t = $\dfrac{r}{u} =\dfrac{75}{40}$

t = 1.875 s

distance covered by Harry

d = 35 + 175 = 210 m

to calculate the acceleration of harry

$s = u t+ \dfrac{1}{2}at^2$

$210 = 50\times 1.875+ \dfrac{1}{2}\times a\times 1.875^2$

a × 3.516 × 0.5 = 116.25

a = 66.126 m/s²

hence, the acceleration of harry is equal to 66.126 m/s²

3 0

3 years ago

Which is the result of mitosis and cytokinesis?

Leno4ka [110]

During cytokinesis, the cytoplasm of the cell is divided in half, and the cell membrane grows to enclose each cell, forming two separate cells as a result. The end result of mitosis and cytokinesis is two genetically identical cells where only one cell existed before.

3 0

3 years ago

Water flows without friction vertically downward through a pipe and enters a section where the cross sectional area is larger. T

djverab [1.8K]

Answer:

$v_{2}$ will be less than $v_{1}$ and $P_{2}$ will be greater than $P_{1}$ .

Explanation:

As we know from the conservation of mass, the rate at which any amount of fluid mass ( $m_{1}$ ) is entering in a system is equal to the rate at which the same amount of fluid mass ( $m_{2}$ ) is leaving the system.

Rate of mass flow can be written as,

$m = \rho A v$

where $\rho$ is the density of the fluid, $A$ is the area through which the fluid is flowing and $v$ is the velocity of the fluid.

Now, according to the problem, as the density of the fluid does not change, we can write

$&& m_{1} = m_{2}\\&or,& \rho A_{1} v_{1} = \rho A_{2} v_{2}\\&or,& \dfrac{v_{2}}{v_{1}} = \dfrac{A_{1}}{A_{2}}$

where $A_{1}$ and $A_{2}$ are the cross-sectional areas through which the fluid is passing and $v_{1}$ and $v_{2}$ are the velocities of the fluid through the respective cross-sectional areas.

As according to the problem, $A_{2} > A_{1}$ , so from the above formula $v_{2} < v_{1}$ .

Also we know that fluid pressure is created by the motion of the fluid through any area. When the fluid gains speed, some of its energy is used to move faster in the fluid’s direction of motion. It causes in a lower pressure.

So, as in this case $v_{2} < v_{1}$ the pressure in the large cross-sectional area $P_{2}$ will be greater than the pressure $P_{1}$ in the small cross sectional area, i.e.,

$P_{2} > P_{1}$ .

6 0

3 years ago

What is the slowest type of radiation?

tekilochka [14]

Velocity is the answer

3 0

3 years ago