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garik1379 [7]
3 years ago
13

Which statement about velocity is true? A. It has only magnitude. B. It has only direction. C. It has magnitude and direction. D

. It is a scalar quantity.
Chemistry
2 answers:
stellarik [79]3 years ago
8 0

Answer: The correct answer is Option C.

Explanation:

There are 2 types of quantities:

1. Scalar quantity: To describe these quantities, only magnitude is required. For example: Speed, distance etc..

2. Vector quantity: To describe these quantities, we require both direction and magnitude. For example: Velocity, displacement etc..

Velocity is defined as the rate of change of displacement.

Mathematically,

v=\frac{d}{t}

where, v = velocity

d = displacement

t = time

As, velocity is a vector quantity.

Hence, the velocity has both magnitude and displacement. Therefore, the correct answer is Option C.

liubo4ka [24]3 years ago
3 0
The answer is C. Velocity is a physical vector quantity. This means that to define velocity, both magnitude and direction are needed. So only C is correct.
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A 45.0 mL solution of 0.0450 M hydroxylamine is extracted with 125 mL of solvent. The distribution constant for the reaction is
julia-pushkina [17]

Answer:

pH = 4.5, concentration = 0.045 M.

pH = 6.5, concentration = 0.175 M.

Explanation:

The ka for the can be calculated by using the formula below;

Ka = 10^-pka = 10^-5.960 = 1.1 × 10^-6

The concentration of hydrogen ion at pH = 4.50 can be calculated as given below;

{H^+ } = 10^-4.50 = 3.2 × 10^-5 M.

(NB=> 10 in this regards means the inverse of log).

The next step is to determine the distribution coefficient which can be calculated by using the formula below;

distribution coefficient = (partition coefficient) × ka / ka + ( concentration of Hydrogen ion,H^+).

distribution coefficient =( 5 × 1.1 × 10^-6 ) / 1.1 × 10^-6 + 3.2 × 10^-5 M. = 5.5 × 10^-6/ 3.2 = 0.00000171875

The fraction remaining from the compound = 45.0 mL / 45.0 mL + (0.00000171875 × 125).

= 0.999995.

Thus, the concentration at pH = 4.5 = 0.999995 × 0.0450 M = 0.045 M

(B). pH=6.50, thus the concentration of Hydrogen ion = 10^-6.5 = 3.2 × 10^-7 M.

distribution coefficient = (partition coefficient) × ka / ka + ( concentration of Hydrogen ion,H^+).

distribution coefficient = (5 × 1.1 × 10^-6)/ 1.1 × 10^-6 + 3.2 × 10^-7 M).

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Therefore, the concentration = 3.9 × 0.0450 M = 0.175 M.

8 0
3 years ago
3 Ni2+(aq) + 2 Cr(OH)3(s) + 10 OH− (aq) → 3 Ni(s) + 2 CrO42−(aq) + 8 H2O(l) ΔG∘ = +87 kJ/mol Given the standard reduction potent
Tom [10]

Answer : The standard reduction potential, E^o_{(Cr^{+6}/Cr^{+3})} is -0.13 V.

Solution : Given,

E^o_{(Ni^{2+}/Ni)}=-0.28V

\Delta G^o=+87KJ/mole=+87000J/mole       (1 KJ = 1000 J)

The net reaction is,

3Ni^{2+}(aq)+2Cr(OH)_3(s)+10OH^-(aq)\rightarrow 3Ni(s)+2CrO^{2-}_4(aq)+8H_2O(l)

The half cell reactions are :

At cathode : Ni^{2+}(aq)+2e^-\rightarrow Ni(s)       E^o_{(Ni^{2+}/Ni)}=-0.28V

At anode : CrO^{2-}_4(aq)+4H_2O(l)+3e^-\rightarrow Cr(OH)_3(s)+5OH^-(aq)  E^o_{(Cr^{+6}/Cr^{+3})}=?

First we have to calculate the E^o_{cell} by using formula,

\Delta G^o=-nFE^o_{cell}

where,

\Delta G^o = Gibbs's free energy

n = number of electrons in a net chemical reaction = 6 electrons

F = Faraday constant = 96485 C

E^o_{cell} = standard cell potential

Now put all the given values in this formula, we get

+87000KJ/mole=-6\times (96485)\times E^o_{cell}\\E^o_{cell}=-0.15V

Now we have to calculate the E^o_{(Cr^{+6}/Cr^{+3})} by using formula,

E^o_{cell}=E^o_{cathode}-E^o_{anode}

E^o_{cell}=E^o_{(Ni^{2+}/Ni)}-E^o_{(Cr^{+6}/Cr^{+3})}

Now put all the given values in this formula, we get

-0.15V=-0.28V-E^o_{(Cr^{+6}/Cr^{+3})}

E^o_{(Cr^{+6}/Cr^{+3})}=-0.13V

Therefore, the standard reduction potential, E^o_{(Cr^{+6}/Cr^{+3})} is -0.13 V.

4 0
4 years ago
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