Answer:
4 cm/s².
Explanation:
From the question given above, the following data were obtained from it:
Initial velocity (u) = 0 cm/s
Final velocity (v) = 40 cm/s
Time (t) = 10 s
Acceleration (a) =?
Acceleration is simply defined as the rate of change of velocity with time. Mathematically, it is expressed as follow:
Acceleration (a) = Change in velocity /time
Acceleration (a) = [final velocity (v) – initial velocity (u)] /time (t)
a = (v – u) /t
With the above formula, we can obtain the acceleration of the ball as follow:
Initial velocity (u) = 0 cm/s
Final velocity (v) = 40 cm/s
Time (t) = 10 s
Acceleration (a) =?
a = (v – u) /t
a = (40 – 0) / 10
a = 40/10
a = 4 cm/s²
Therefore, the acceleration of the ball is 4 cm/s²
Answer:
v = ((m + M) / m)*√(2*g*h)
Explanation:
Given
m = mass of the projectile
M = mass of the ballistic pendulum
v = initial speed of the projectile
v' = speedof the system (pendulum + projectile) after the inelastic collision
h = maximum height reached for the system
Knowing that is an inelastic collision we have
m*v + M*(0) = (m+M)*v'
⇒ v' = m*v / (m+M)
After the collision, we apply the Principle of the Conservation of Energy
Ki + Ui = Kf + Uf
where
Ui = Kf = 0 J
then
Ki = Uf
0.5*(m+M)*v'² = (m+M)*g*h
⇒ 0.5*v'² = g*h
⇒ v'² = 2*g*h
⇒ (m*v / (m+M))² = 2*g*h
⇒ v = ((m+M) / m)*√(2*g*h)
When you mix two chemicals then they are not the same as they were when you before you mixed them so true
Answer:
3^15 / 3^3 = 3^12 * 3^3 / 3^3 = 3^12
The Law of Exponents applies here
3^15 x 3^3 is a product, not a quotient
3^15 x 3^3 = 3^18
Work done by the sprinter in first 2.5 s will be 702.699 J.
Work done is the product of force and distance covered.
- Mathematically, W = Force * Distance
Mass of the sprinter = 58 kg
Distance covered by the sprinter = s = 60 m
Total time taken by the sprinter = t = 7.8 s
- According to the Equations of motion S = ut +
u = initial velocity = 0
a = constant acceleration
60 =
60.84 a = 60 * 2
a = 1.97
For a = 1.97 and t = 2.5 s
d =
Here also u is '0' because the distance is being measured from the starting point.
d =
d = 6.15 m
Work done by the sprinter = F * d
Force = mass * acceleration
F = 58 * 1.97
F = 114.26 N
distance for first 2.5 sec is 6.15 m
Therefore Work done = 6.15 * 114.26
W = 702.699 J
Work done by the sprinter is 702.699 J.
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