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svet-max [94.6K]
3 years ago
10

What does carbon monoxide bind to blocks oxidative metabolism?

Chemistry
1 answer:
zavuch27 [327]3 years ago
8 0
Metabolism is when you don’t gain weight after eating a lot.
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A mixture of reactants and products for the reaction shown below is at
zavuch27 [327]

If the volume of the container were increased to 4.0 L, more N₂ and H₂ would be produced (Option D)

<h3>What is chemical equilibrium? </h3>

This is simply defined as a state in a chemical system where there is no observable change in the properties of the system with time.

<h3>Principle of chemical equilibrium </h3>

A French scientist postulated a principle which helps us to understand a chemical system in equilibrium.

The principle states as follow:

If a an external constraint such as change in temperature, pressure or concentration is imposed on a system in equilibrium, the equilibrium will shift so as to neutralize the effect.

<h3>How to determine what will happen if the volume of the container is increased from 2 L to 4 L</h3>

From the principle given above, we can see that volume does not affect equilirium position.

However, from Boyle's law, we understood that pressure and volume are in invest relationship.

Thus, increasing volume simply means decreasing pressure.

A decrease in pressure will favors the side where there is an increase in volume.

Let us consider the equation from the question:

N₂(g) + 3H₂(g) <=> 2NH₃(g)

  • Volume of reactants = 1 + 3 = 4 L
  • Volume of products = 2 L

Thus, we can conclude that increasing the volume (i.e decreasing the pressure) of the reaction will favors the backward reaction, hence, more N₂ and H₂ would be produced.

Learn more about chemical equilibrium:

brainly.com/question/4289021

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5 0
2 years ago
In a spacecraft tge carbon dioxide exhaled by the astronaut can be removed by the reaction with lithium hydroxide, LiOH accordin
quester [9]

Answer:

30 moles

Explanation:

From the equation it is a one - to - one reaction

3 0
2 years ago
Consider the following system at equilibrium:A(aq)+B(aq) &lt;---&gt; 2C(aq)Classify each of the following actions by whether it
velikii [3]

Explanation:

Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.

This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

  • On addition of reactant at equilibrium shifts the equilibrium in forward direction.
  • On addition of product at equilibrium shifts the equilibrium in backward direction.
  • On removal of reactant at equilibrium shifts the equilibrium in backward direction.
  • On removal of product at equilibrium shifts the equilibrium in forward direction.

A(aq)+B(aq)\rightleftharpoons 2C(aq)

Reactants = A , B

Product = C

1. Increase A

On increasing the amount of A at equilibrium will shift the equilibrium in forward or rightward direction.

2. Increase B

On increasing the amount of B at equilibrium will shift the equilibrium in forward or rightward direction.

3. Increase C

On increasing the amount of C at equilibrium will shift the equilibrium in backward or leftward direction.

4. Decease A

On decreasing the amount of A at equilibrium will shift the equilibrium in backward or leftward direction.

5. Decease B

On decreasing the amount of B at equilibrium will shift the equilibrium in backward or leftward direction.

6. Decease C

On decreasing the amount of C at equilibrium will shift the equilibrium in forward or rightward direction.

7. Double A and Halve B

Equilibrium constant of the reaction = K

K=\frac{[C]^2}{[A][B]}

On doubling A and halving B, equilibrium constant of the reaction = K'

K'=\frac{[C]^2}{[2A][\frac{B}{2}]}=\frac{[C]^2}{[A][B]}

The value of equilibrium constant K' is equal to K, which means that equilibrium will not shift in any direction.

8. Double both B and C

Equilibrium constant of the reaction = K

K=\frac{[C]^2}{[A][B]}

On doubling B and C, equilibrium constant of the reaction = K'

K'=\frac{[2C]^2}{[A][2B]}=\frac{4[C]^2}{[A][2B]}=\frac{2[C]^2}{[A][B]}

K' = 2 K

The value of equilibrium constant K' is double the K, which means that product is increasing which means that equilibrium will shift in backward or leftward direction.

5 0
3 years ago
Balance the equation and identify the type of reaction for ? p4(s) + ? ca(s) → ? ca3p2(s).
Kazeer [188]
There are different kinds of reactions. To name some, these are the synthesis reaction, decomposition reaction, single-replacement reaction, double-replacement reaction, combustion reaction, redox reaction, etc. For this type of reaction involving two reactants to yield only one product, <em>this is a synthesis reaction.</em>

<em>P₄ (s) + 6 Ca (s) --> 2 Ca₃P₂ (s)</em>
3 0
3 years ago
What do Hubris mean?
Alona [7]

Hubris: excessive pride or self-confidence.

7 0
3 years ago
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