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4 years ago

Process found in both photosynthesis and cellular respiration

Chemistry

1 answer:

aalyn [17]4 years ago

6 0

It would be D light dependent reaction, I don’t have much of a explanation but I promise it’s D

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People should be more concerned about the global water budget than the local water budget.

Paraphin [41]

True because you shouldn’t be selfish and share with the world

7 0

3 years ago

2K + 2HBr → 2 KBr + H2

Inessa [10]

Answer:

$\large \boxed{\text{0.0503 g}}$

Explanation:

The limiting reactant is the reactant that gives the smaller amount of product.

Assemble all the data in one place, with molar masses above the formulas and masses below them.

M_r: 39.10 80.41 2.016

2K + 2HBr ⟶ 2KBr + H₂

m/g: 5.5 4.04

a) Limiting reactant

(i) Calculate the moles of each reactant

$\text{Moles of K} = \text{5.5 g} \times \dfrac{\text{1 mol}}{\text{31.10 g}} = \text{0.141 mol K}\\\\\text{Moles of HBr} = \text{4.04 g} \times \dfrac{\text{1 mol}}{\text{80.91 g}} = \text{0.049 93 mol HBr}$

(ii) Calculate the moles of H₂ we can obtain from each reactant.

From K:

The molar ratio of H₂:K is 1:2.

$\text{Moles of H}_{2} = \text{0.141 mol K} \times \dfrac{\text{1 mol H}_{2}}{\text{1 mol K}} = \text{0.0703 mol H}_{2}$

From HBr:

The molar ratio of H₂:HBr is 3:2.

$\text{Moles of H}_{2} = \text{0.049.93 mol HBr } \times \dfrac{\text{1 mol H}_{2}}{\text{1 mol HBr}} = \text{0.024 97 mol H}_{2}$

(iii) Identify the limiting reactant

HBr is the limiting reactant because it gives the smaller amount of NH₃.

b) Excess reactant

The excess reactant is K.

c) Mass of H₂

$\text{Mass of H}_{2} = \text{0.024 97 mol H}_{2} \times \dfrac{\text{2.016 g H}_{2}}{\text{1 mol H}_{2}} = \textbf{0.0503 g H}_{2}\\ \text{The mass of hydrogen is $\large \boxed{\textbf{0.0503 g}}$ }$

3 0

3 years ago

8.45 cm - 3.55 cm = ?

lyudmila [28]

Answer:

4.9cm or 4.90cm

Explanation:

Use column method and align the numbers. Make sure you add the decimal point before you write the answer, otherwise the value would be wrong.

6 0

3 years ago

Read 2 more answers

A biochemist is attempting to replicate a chemical reaction that commonly takes place in cells. during the chemical reaction, st

BartSMP [9]

If the concentration of enzyme increases, then reaction should speed up (answer C).
enzyme speeds up a chemical reaction by lowering activation energy to provide an alternative pathway of reaction mechanism. assuming that enzyme which usually is the limiting factor, the increase of enzyme concentration should lead to more product formation i.e. maltose from the breakdown of starch.
the enzyme discussed here should be amylase.

higher temperature beyond optimum value enzyme found in our human body will usually least to denaturation of active site of enzyme. hence lead to loss of enzyme activity permanently.

4 0

3 years ago

H2SO4 + 2NaOH → 2H2O + Na So.

gayaneshka [121]

Answer:

2 mol H

Explanation:

For every 2 mol of NaOH, we're reacting 2 mol of H2O. In order to figure out how many mol of H are needed, it needs to be set up stochiometrically. Starting off with the given value, 1 mol of NaOH, we can then make a mol to mol ratio. For 2 mol of NaOH, we have 2 mol of H2O. For every 2 mol of H2O, we have 4 mol of H (this is because we are multiplying the coefficient by the subscript: 2 × 2). Now, we can solve for our answer.

1 mol NaOH × (2 mol H₂O / 2 mol NaOH) × (4 mol H / 2 mol H₂O)

= 2 mol H

Thus, we get 2 mol of H are needed to completely react 1 mol of NaOH.

7 0

4 years ago