All categories

3 years ago

ithout heat from the Sun, the water cycle would A) reverse. B) not work. C) slow down. D) not be affected.

2 answers:

8 0

Hey there!
The first step of the cycle is evaporation, where heat from the sun heats water into water vapor and it condenses. If there's no heat, there's no cycle- so no sun, no cycle.
Hope this helps!

lawyer [7]3 years ago

7 0

B) Not work since decrease in temperature wouldnt cause evaporation or reverse in cycle.

You might be interested in

A proton (mass m 1.67 x 1027 kg) is being accelerated along a straight line at 1.4 x 1015 m/s2 in a machine. The proton has an i

BaLLatris [955]

Answer:

Part a)

$v_f = 2.569 \times 10^7 m/s$

Part b)

$\Delta K = 7.014 \times 10^{-14} J$

Explanation:

Part a)

As we know that proton is accelerated uniformly so we can use kinematics here to find the final speed

so we know that

$v_i = 2.4 \times 10^7 m/s$

$d = 3 cm$

$a = 1.4 \times 10^{15} m/s^2$

so we will have

$v_f^2 - v_i^2 = 2 a d$

$v_f^2 - (2.4 \times 10^7)^2 = 2(1.4 \times 10^{15})(0.03)$

$v_f^2 = 6.6 \times 10^{14}$

$v_f = 2.569 \times 10^7 m/s$

Part b)

Now increase in kinetic energy is given as

$\Delta K = \frac{1}{2}m(v_f^2 - v_i^2)$

$\Delta K = \frac{1}{2}(1.67 \times 10^{-27})[(2.569 \times 10^7)^2 - (2.4 \times 10^7)^2]$

$\Delta K = 7.014 \times 10^{-14} J$

7 0

2 years ago

Pls help it's due today

mario62 [17]

Answer:

Breh seriously. Ugh fine.

1.B

2.D

3.C

4.C

5.D,A and B

6.A,C and D

3 0

2 years ago

Scientific work is currently underway to determine whether weak oscillating magnetic fields can affect human health. For example

iragen [17]

Given Information:

Magnetic field = B = 1×10⁻³ T

Frequency = f = 72.5 Hz

Diameter of cell = d = 7.60 µm = 7.60×10⁻⁶ m

Required Information:

Maximum Emf = ?

Answer:

Maximum Emf = 20.66×10⁻¹² volts

Explanation:

The maximum emf generated around the perimeter of a cell in a field is given by

Emf = BAωcos(ωt)

Where A is the area, B is the magnetic field and ω is frequency in rad/sec

For maximum emf cos(ωt) = 1

Emf = BAω

Area is given by

A = πr²

A = π(d/2)²

A = π(7.60×10⁻⁶/2)²

A = 45.36×10⁻¹² m²

We know that,

ω = 2πf

ω = 2π(72.5)

ω = 455.53 rad/sec

Finally, the emf is,

Emf = BAω

Emf = 1×10⁻³*45.36×10⁻¹²*455.53

Emf = 20.66×10⁻¹² volts

Therefore, the maximum emf generated around the perimeter of the cell is 20.66×10⁻¹² volts

8 0

2 years ago

A vector is 14.4 m long and

MaRussiya [10]

Answer:

Explanation:

The x-component is found in the magnitude of the vector times the cosine of the angle.

$A_x=14.4cos133$ and, to 3 sig dig,

$A_x=-9.82m$

3 0

3 years ago

Two identical balls collide one was initially at rest. after the collision one of the balls has a velocity of 3 m/s south. the o

Butoxors [25]

Two identical balls collide head on. The initial velocity of one is 0.75 m/s east, while that of the other one is 0.43 m/s west.

4 0

2 years ago