Answer:
Part a)

Part b)

Explanation:
Part a)
As we know that proton is accelerated uniformly so we can use kinematics here to find the final speed
so we know that



so we will have




Part b)
Now increase in kinetic energy is given as

![\Delta K = \frac{1}{2}(1.67 \times 10^{-27})[(2.569 \times 10^7)^2 - (2.4 \times 10^7)^2]](https://tex.z-dn.net/?f=%5CDelta%20K%20%3D%20%5Cfrac%7B1%7D%7B2%7D%281.67%20%5Ctimes%2010%5E%7B-27%7D%29%5B%282.569%20%5Ctimes%2010%5E7%29%5E2%20-%20%282.4%20%5Ctimes%2010%5E7%29%5E2%5D)

Answer:
Breh seriously. Ugh fine.
1.B
2.D
3.C
4.C
5.D,A and B
6.A,C and D
Given Information:
Magnetic field = B = 1×10⁻³ T
Frequency = f = 72.5 Hz
Diameter of cell = d = 7.60 µm = 7.60×10⁻⁶ m
Required Information:
Maximum Emf = ?
Answer:
Maximum Emf = 20.66×10⁻¹² volts
Explanation:
The maximum emf generated around the perimeter of a cell in a field is given by
Emf = BAωcos(ωt)
Where A is the area, B is the magnetic field and ω is frequency in rad/sec
For maximum emf cos(ωt) = 1
Emf = BAω
Area is given by
A = πr²
A = π(d/2)²
A = π(7.60×10⁻⁶/2)²
A = 45.36×10⁻¹² m²
We know that,
ω = 2πf
ω = 2π(72.5)
ω = 455.53 rad/sec
Finally, the emf is,
Emf = BAω
Emf = 1×10⁻³*45.36×10⁻¹²*455.53
Emf = 20.66×10⁻¹² volts
Therefore, the maximum emf generated around the perimeter of the cell is 20.66×10⁻¹² volts
Answer:
Explanation:
The x-component is found in the magnitude of the vector times the cosine of the angle.
and, to 3 sig dig,

Two identical balls collide<span> head on. The </span>initial velocity<span> of </span>one<span> is 0.75 </span>m/s<span> east, while that of the </span>other one<span> is 0.43 </span>m/s west<span>.</span>