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Sveta_85 [38]
3 years ago
8

During which process would the ratio of uranium 238 to lead 206 be used?

Chemistry
2 answers:
vova2212 [387]3 years ago
6 0

Answer:

The ratio of the amounts of U 238 and Pb 206 in a rock sample enables the age of the rock to be estimated using the technique of radiometric dating. It moves back in the periodic table until the isotope falls in the band of stability at Pb 206.

cestrela7 [59]3 years ago
6 0

Answer: The ratio of the amounts of U 238 and Pb 206 in a rock sample enables the age of the rock to be estimated using the technique of radiometric dating. It moves back in the periodic table until the isotope falls in the band of stability at Pb 206.

Explanation:

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Answer:

Explanation:

meiosis

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4 0
2 years ago
Hydrogen sulfide decomposes according to the following reaction: 2H2S(g) ⇋ 2H2(g) + S2(g) Kc=9.30x10-8 at 700.°C.If 0.45 mol of
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Answer:

[H₂] = 1.61x10⁻³ M

Explanation:

2H₂S(g) ⇋ 2H₂(g) + S₂(g)

Kc = 9.30x10⁻⁸ = \frac{[H_{2}]^2[S_{2}]}{[H_{2}S]^2}

First we <u>calculate the initial concentration</u>:

0.45 molH₂S / 3.0L = 0.15 M

The concentrations at equilibrium would be:

[H₂S] = 0.15 - 2x

[H₂] = 2x

[S₂] = x

We <u>put the data in the Kc expression and solve for x</u>:

\frac{(2x^2) * x}{(0.15-2x)^2}=9.30x10^{-8}

\frac{4x^3}{0.0225-4x^2}=9.30*10^{-8}

We make a simplification because x<<< 0.0225:

\frac{4x^3}{0.0225} =9.30*10^{-8}

x = 8.058x10⁻⁴

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5 0
3 years ago
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Answer:

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