This question uses mole ratios. firstly, we look at how many moles of H2 are produced for every mole of HCl: from 1 Hcl, we get half a mole of H2. therefore, however many moles of HCl are present in the 0.075 L of 1.0M HCl, half that number of H2 moles will be produced.
n=cv
=0.0750 x 1.0
=0.075 mol HCl
n(H2)= 0.5 x n(HCl)
=0.0375 moles of H2
Answer:
The diameter of the oil molecule is
.
Explanation:
Mass of the oil drop = 
Density of the oil drop = 
Volume of the oil drop: v


Thickness of the oil drop is 1 molecule thick.So, let the thickness of the drop or diameter of the molecule be x.
Radius of the oil drop on the water surface,r = 41.8 cm = 0.418 m
1 cm = 0.01 m
Surface of the sphere is given as: a = 

Volume of the oil drop = v = Area × thickness


The thickness of the oil drop is
and so is the diameter of the molecule.
Answer: One of the most common iron oxides is iron (III) oxide, known as rust. The chemical formula for rust is Fe2O3. Rust is formed when iron reacts with oxygen in moist air. The following chemical equation represents the reaction: 4Fe + 3O2 → 2Fe
2BF₃ + 3Li₂SO₃ ----> B₂(SO₃)₃ + <u>6LiF
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