The train accelerates at the rate of 20 for some time, until it's just exactly
time to put on the brakes, decelerate at the rate of 100, and come to a
screeching stop after a total distance of exactly 2.7 km.
The speed it reaches while accelerating is exactly the speed it starts decelerating from.
Speed reached while accelerating = (acceleration-1) (Time-1) = .2 time-1
Speed started from to slow down = (acceleration-2) (Time-2) = 1 time-2
The speeds are equal.
.2 time-1 = 1 time-2
time-1 = 5 x time-2
It spends 5 times as long speeding up as it spends slowing down.
The distance it covers speeding up = 1/2 A (5T)-squared
= 0.1 x 25 T-squared = 2.5 T-squared.
The distance it covers slowing down = 1/2 A (T-squared)
= 0.5 T-squared.
Total distance = 2,700 meters.
(2.5 + .5) T-squared = 2,700
T-squared = 2700/3 = 900
T = 30 seconds
The train speeds up for 150 seconds, reaching a speed of 30 meters per sec
and covering 2,250 meters.
It then slows down for 30 seconds, covering 450 meters.
Total time = <u>180 sec</u> = 3 minutes, minimum.
Observation:
This solution is worth more than 5 points.
In solid and liquid the matter can occupy the 90 in³ and 157.1 in³ volume.
The matter in gaseous state can be expanded to occupy the volumes of the container.
<h3>
Volume of each of the container</h3>
The volume of each of the container is calculated as follows;
<h3>Volume of the rectangular container</h3>
V = 5 in x 6 in x 3 in
V = 90 in³
<h3>Volume of the cylindrical container</h3>
V = πr²h
V = (π)(2.5 in)²(8 in)
V = 157.1 in³
<h3>Volume of the matter</h3>
Vm = 3 in x 4 in x 5 in
Vm = 60 in³
<h3>Matter in solid and liquid state</h3>
Matter has fixed volume in solid and liquid state.
In solid and liquid the matter can occupy the 90 in³ and 157.1 in³ volume.
<h3>Matter in gaseous state</h3>
Matter has no definite volume in gaseous state.
The matter in gaseous state can be expanded to occupy the volumes of the container.
Learn more about states of matter here:
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<u>a).</u>
Kenny's potential energy at the top becomes kinetic energy at the bottom.
(M G H) = 1/2 (M V²)
Divide each side by 'M': G H = 1/2 V²
Multiply each side by 2: 2 G H = V²
Take the square root of each side: V = √(G H)
= √(9.8 x 3.2) = <em><u>5.6 m/s .</u></em>
<u>b).</u>
Notice in the solution for a). that each side of the equation was divided
by 'M'. The answer didn't depend on Kenny's mass, and it doesn't depend
on Cartman's mass either. Cartman and Kenny are both moving at the
same speed when they reach the bottom.
<u>c).</u>
Notice in the solution for a). that each side of the equation was divided
by 'M'. The answer didn't depend on Kenny's mass. It didn't depend on
Cartman's mass either, and it doesn't depend on Kyle's mass either, either.
Each of them is moving at the same speed when he reaches the bottom.
The same also applies to girls as well, too.
If an initial cardioversion attempt is unsuccessful in a 33-pound child, you should repeat the procedure using 30 joules.
Cardioversion
Cardioversion is a medical therapy that uses medications or electricity to restore a normal heart rhythm to someone who has an abnormally high heart rate (tachycardia) or another cardiac arrhythmia. Synchronized electrical cardioversion restores the activity of the heart's electrical conduction system by applying a therapeutic dosage of electric current to the heart at a specified point in the cardiac cycle. (Defibrillation is the most efficient form of resuscitation for cardiac arrest caused by ventricular fibrillation and pulseless ventricular tachycardia. It delivers a therapeutic dosage of electric current to the heart at an unpredictable point in the cardiac cycle. Chemical cardioversion, also known as pharmacologic cardioversion, substitutes antiarrhythmic drugs for an electrical shock.
To learn more about cardioversion refer here:
brainly.com/question/11601470
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W=mass X gravity
<span>since the weight is computed </span>
<span>mass=w / gravity </span>
<span>so </span>
<span>mass=1100 / 9.81 </span>
<span>MASS=112.1304KG </span>
<span>PE=MGH </span>
<span>=112.1304 x 9.81 x 2.2 </span>
<span>PE=2420 JOULE </span>