Answer:
A. N = L/πD
B. N = 389 turns
C. L₂ = DN
D. L₂ = 17.5 m
E. B = 2.3 x 10⁻⁴ Web
Explanation:
A.
For each number of turn a length of wire equal to the circumference of tube. Therefore, the no. of turns can be given as:
N = L/2πr
<u>N = L/πD</u>
where,
N = No. of turns
D = Diameter of tube
L = Length of wire
B.
using values in the equation, we get:
N = 55 m/π(0.045 m)
<u>N = 389 turns</u>
C.
Since, there is only one layer of loop. Therefore, the length of solenoid can be easily found out by adding the diameter of wire for each turn. Hence:
L₂ = DN
where,
L₂ = Length of the solenoid
D = diameter of wire
N = No. of Turns
D.
using values in the equation we get:
L₂ = (0.045 m)(389)
<u>L₂ = 17.5 m</u>
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E.
The magnitude of magnetic field inside solenoid is given by the formula:
B = μ₀NI/L₂
where,
B = Magnetic field inside solenoid
μ₀ = permeability = 4π x 10⁻⁷ T/A.m
I = current = 8.5 A
Therefore,
B = (4π x 10⁻⁷ T/A.m)(389)(8.5 A)/17.5 m)
<u>B = 2.3 x 10⁻⁴ Web</u>