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SSSSS [86.1K]
4 years ago
9

What weighs more, a ton of feathers or a ton of bricks

Physics
2 answers:
torisob [31]4 years ago
5 0
They are the same exact weight. hope this helped!  :)
SVETLANKA909090 [29]4 years ago
3 0
A ton of bricks weighs more than a ton of feathers.

hope this helps!
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A motorboat traveling on a straight course slows
never [62]

Answer:

2.572 m/s²

Explanation:

Convert the given initial velocity and final velocity rates to m/s:

  • 65 km/h → 18.0556 m/s
  • 35 km/h → 9.72222 m/s

The motorboat's displacement is 45 m during this time.

We are trying to find the acceleration of the boat.

We have the variables v₀, v, a, and Δx. Find the constant acceleration equation that contains all four of these variables.

  • v² = v₀² + 2aΔx

Substitute the known values into the equation.

  • (9.72222)² = (18.0556)² + 2a(45)
  • 94.52156173 = 326.0046914 + 90a
  • -231.4831296 = 90a
  • a = -2.572

The magnitude of the boat's acceleration is |-2.572| = 2.572 m/s².

3 0
3 years ago
Which location would the selected items BEST fit on the nuclear energy diagram?
Sladkaya [172]
Your answer is c) Fusion

7 0
4 years ago
Read 2 more answers
An inductor with an inductance of .5 henrys (H) is to be connected to a 60 Hz circuit. What will the inductive reactance (X L) b
Anika [276]

Answer:

1885.2 ohms

Explanation:

Step one:

given data

L=5H

f=60Hz

Required

The inductive reactance of the inductor

Step two:

Applying the expression

XL= 2πfL

substitute

XL=2*3.142*60*5

XL=1885.2 ohms

4 0
3 years ago
Which body sense (choose only 1) do you think is most important? Explain why and provide at least 2
larisa [96]

Answer:

ears

Explanation:

4 0
3 years ago
3. Two balls are rolling toward each other. One has a momentum of 85kg*m/s, and the other has a momentum of -85kg*m/s. What will
irakobra [83]

Answer:

The total momentum is zero.

Explanation:

This problem can be solved by applying the momentum conservation theorem and the amount of motion. This theorem tells us that the amount of motion is conserved before and after a collision.

In the next equation, we will write to the left of the equal sign the amount of motion before the collision and to the right the amount of motion after the collision.

(P_{1})-(P_{2})=P_{3}

where:

P₁ = momentum of the ball moving to the right, before the collision = 85 [kg*m/s]

P₂ = momentum of the ball moving to the left, before the collision = - 85 [kg*m/s]

P₃ = Final momentum after the collision [kg*m/s]

(85) - 85 = P_{3}\\P_{3}= 0

There is no movement of any of the balls, they remain at rest after the impact.

5 0
3 years ago
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