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Paul [167]
3 years ago
11

When jumping, a flea rapidly extends its legs, reaching a takeoff speed of 1.0 m/s over a distance of 0.50 mm find acceleration.

How long does it take the flea to leave the ground after it begins pushing off?
Physics
1 answer:
Anna [14]3 years ago
3 0

Solution:

In this question we have given,

initial velocity,u = 0

final velocity, v = 1m/s

displacement =.5mm             (Because 1mm=.001m)

We have to find

1.acceleration

2. Time

1. we know third equation of motion is given as,

v^{2} =u^{2} + 2as............(1)

Put values of v,u and s in equation (1)

[tex]s=1^{2} = 0^{2} +2X.0005Xa\\1= .001a\\therefore, a = 1/.001\\ a= 1000m/s^{2}

2. We know First equation of motion is given as

v=u+at......................(2)

put values of v, u and a in equation(2)

1= 0 + 1000t\\t= 1/1000\\t= 0.001s

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Two very long uniform lines of charge are parallel and are separated by 0.300 m. each line of charge has charge per unit length
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linear charge density of system of two line charges is given as

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now as we know that electric field due to a line charge at some distance from it is given by

E = \frac{\lambda}{2\pi \epsilon_0 r}

so here we will first find the electric field of first line charge at the position of other line charge

E = \frac{5.20 * 10^{-6}}{2 \pi * 8.85 * 10^{-12}* 0.300}

E = 312000 N/C

now as we know that

F = qE

here q = charge on the line charge system at which force is required

E = electric field on that system of charge where force is required

now we can find the charge by

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q = 5.20 * 10^{-6}* 0.05 = 0.26 * 10^{-6} C

Now using the above formula

F = qE

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so force on the part of wire is F = 0.0811 N

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A car takes 10 s to go from v = 0 m/s to v = 25 m/s at constant acceleration. If you wish to find the distance traveled using th
german

Initial velocity (u) = 0 m/s

Final velocity (v) = 25 m/s

time taken (t) = 10s

acceleration (a) = ?

Now,

Acceleration is rate of change of velocity, so formula is

a = (v - u)/t

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Use this value of a.

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Answer: radiant energy

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