Answer:
gases (hydrogen, helium, nitrogen, oxygen, fluorine, neon, chlorine, argon, krypton, xenon and radon); one is a liquid (bromine); and a few are solids (carbon, phosphorus, sulfur, selenium, and iodine).
Explanation:
Can someone help me with my last question?
Answer:
1.17 M
Explanation:
Step 1: Given data
Molar concentration of Li₃PO₄: 0.390 M
Step 2: Write the reaction for the dissociation of Li₃PO₄
Lithium phosphate is a strong electrolyte that dissociates according to the following equation:
Li₃PO₄(aq) ⇒ 3 Li⁺(aq) + PO₄³⁻(aq)
Step 3: Calculate the molar concentration of lithium ions
The molar ratio of Li₃PO₄ to Li⁺ is 1:3. The molar concentration of Li⁺ is 3/1 × 0.390 M = 1.17 M.
Answer:
Explanation:
The formation of ammonia that occurred by the reaction of nitrogen and ammonia is expressed as:
⇄ ![2NH_{3(g)}](https://tex.z-dn.net/?f=2NH_%7B3%28g%29%7D)
where;
The reactants are:
Hydrogen and nitrogen
The product is ammonia.
For the reaction, the equilibrium constant can be expressed as:
![K = \dfrac{[product]}{[reactants]}](https://tex.z-dn.net/?f=K%20%3D%20%5Cdfrac%7B%5Bproduct%5D%7D%7B%5Breactants%5D%7D)
![K = \dfrac{[NH_3]^2}{[N_2]^3[H_2]^3}](https://tex.z-dn.net/?f=K%20%3D%20%5Cdfrac%7B%5BNH_3%5D%5E2%7D%7B%5BN_2%5D%5E3%5BH_2%5D%5E3%7D)
From the equilibrium constant conditions, the formation of ammonia and its decomposition due to its reversible reaction back to hydrogen and nitrogen are equal. It implies that the rate of the forward reaction is also equal to that of the backward reaction.
Thus, during when equilibrium is obtained;
Hydrogen, Nitrogen, and Ammonia are present.