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mars1129 [50]
3 years ago
9

A star is located 12.5 parsecs away from us. What is its parallax angle? D = 1/p

Physics
2 answers:
mars1129 [50]3 years ago
8 0

Answer:

<h2>The parallax angle is 0.08 seconds of arc.</h2>

Explanation:

In the image attached you can observe where is the parallax angle placed.

Now, this parallax angle is inversely proportional to the distance measured in parsecs. That means, the greater the distance, the smaller the parallax angle.

Mathematically, it's defined as

D=\frac{1}{p}

Where D=12.5 pc, replacing this value, we have

D=\frac{1}{p}\\p=\frac{1}{D}=\frac{1}{12.5 pc}  =0.08''

Therefore, the parallax angle is 0.08 seconds of arc.

Rudiy273 years ago
7 0
You are given a star that is located 12.5 parsecs away from us (let us assume that the reference point is on earth). You are tasked to find the parallax angle. The equation to get the parallax angle is D = 2 (AU)/ tanФ wherein D is the distance of the star from the earth, AU is the distance of earth from the sun and Ф is the parallax angle. Note that 1 parsec = 1,000,000,000,000 million meters and that the distance of earth to the sun is about 149,600,000,000 meters.

D = 2 (AU)/ tanФ
tan Ф = 2 (AU)/D
Ф = tan⁻¹ [ 2(AU) / D]
Ф = tan⁻¹ [ 2(149,600,000,000) / 12,500,000,000,000]
Ф = 1.37°
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EastWind [94]

Answer:

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a)

We know that

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b)

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q=+2.90 µC

Change in electric potential energy ΔU given as

ΔU = q .ΔV

\Delta U=2.9\times 10^{-6}\times 6.48\times 10^3\ J

ΔU =18.79 mJ

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3 years ago
The Moon's center is 3.9x10 m from Earth's center. The Moon is 1.5x10^8 km from the Sun's center. If the mass of the Moon is 7.3
nika2105 [10]

Explanation:

It is given that The Moon's center is 3.9x10⁸ m from Earth's center. The moon 1.5x10⁸ km from the Sun's center. We need to find the ratio of the gravitational forces exerted by Earth and the Sun on the Moon.

The gravitational force is given by :

F=\dfrac{Gm_em_m}{r^2}

It means F\propto \dfrac{1}{r^2}

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\dfrac{F_1}{F_2}=\dfrac{r_2}{r_1}

r₁ = 3.9x10⁸ km

r₂= 1.5x10⁸ km

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\dfrac{F_1}{F_2}=\dfrac{1.5\times 10^8}{3.9\times 10^8}\\\\\dfrac{F_1}{F_2}=\dfrac{5}{13}

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Select the options that best complete the statement.
andriy [413]

Answer:

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Explanation:

For any positive charge the electric field emerges radially outwards and it goes radially inwards for the negative charges.

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