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Keith_Richards [23]
3 years ago
6

At room temperature, the element bromine is a liquid with a density of 3.12 g/mL.

Chemistry
1 answer:
Svetlanka [38]3 years ago
5 0

Answer:

A. 1691.04 g

B. 19.23 mL

Explanation:

The following data were obtained from the question:

Density of bromine = 3.12 g/mL.

A. Determination of the mass of bromine.

Density of bromine = 3.12 g/mL.

Volume of bromine = 542 mL

Mass of bromine =?

Density = mass /volume

3.12 = mass /542

Cross multiply

Mass of bromine = 3.12 × 542

Mass of bromine = 1691.04 g

B. Determination of of volume of bromine.

Density of bromine = 3.12 g/mL.

Mass of bromine = 60 g

Volume of bromine =...?

Density = mass /volume

3.12 = 60 / volume

Cross multiply

3.12 × volume = 60

Divide both side by 3.12

Volume of bromine = 60/3.12

Volume of bromine = 19.23 mL.

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Answer:

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Explanation:

From the question we are told that

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From the reaction we see that

   1 mole of  Mg(ClO_4)_2  is formed by 2 moles of Cl^{-} 1 mole of  Mg^{2+} and 4  O^{2-}

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   4.90  moles of  Mg(ClO_4)_2   will produce  (2 * 4.90) moles of  Cl^{-} ,

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                                                    (39.2) moles of  O^{2-}

                           

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