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Keith_Richards [23]
2 years ago
6

At room temperature, the element bromine is a liquid with a density of 3.12 g/mL.

Chemistry
1 answer:
Svetlanka [38]2 years ago
5 0

Answer:

A. 1691.04 g

B. 19.23 mL

Explanation:

The following data were obtained from the question:

Density of bromine = 3.12 g/mL.

A. Determination of the mass of bromine.

Density of bromine = 3.12 g/mL.

Volume of bromine = 542 mL

Mass of bromine =?

Density = mass /volume

3.12 = mass /542

Cross multiply

Mass of bromine = 3.12 × 542

Mass of bromine = 1691.04 g

B. Determination of of volume of bromine.

Density of bromine = 3.12 g/mL.

Mass of bromine = 60 g

Volume of bromine =...?

Density = mass /volume

3.12 = 60 / volume

Cross multiply

3.12 × volume = 60

Divide both side by 3.12

Volume of bromine = 60/3.12

Volume of bromine = 19.23 mL.

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Source: https://chemiday.com/en/reaction/3-1-0-949

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Answer:

6.2846

Explanation:

Given that:-

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The equilibrium reaction is:-

CH_4+H_2O\rightleftharpoons 3H_2+CO

The expression for equilibrium constant is:

K_{c}=\frac {\left [ H_2 \right ]^3\left [ CO \right ]}{\left [ CH_4 \right ]\left [ H_2O \right ]}

Applying the values as:-

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Studentka2010 [4]

The balanced molecular equation for the given reaction is:

2CH_3COOH(aq) \ + \ Ba(OH)_2(aq) \rightarrow \ Ba(CH_3COO)_2(aq) + 2H_2O(l).

<h3>FURTHER EXPLANATION</h3>

To check that the equation is balanced count how many atoms are present for each element in the reactant and product side. If they are the same before and after reaction for all elements, then the reaction is deemed balanced.

The atom counting for the equation is shown below:

2CH_3COOH(aq) \ + \ Ba(OH)_2(aq) \rightarrow \ Ba(CH_3COO)_2(aq) + 2H_2O(l).

<u>Reactants </u>                  →                 <u>Products</u>

C:  (2 x 2) =4                                  C: (2 x 2) = 4

H: (2 x 4) + (1 x 2) =10                    H: (3 x 2) + (2 X 2) = 10

O: (2 x 2) + (1 x 2) = 6                    O: (2 x 2) + (2 x 1) = 6

Ba: 1                                               Ba: 1

Since the number of atoms of each element are similar in the reactants and products, the equation is balanced.

To determine the state of the substances, consider their solubility.

The reactants are both aqueous (aq) as indicated in the problem.

The first product, Ba(CH_3COO)_2 is aqueous (aq) because based on the solubility rule, it will dissolve in water. Acetates are generally soluble.

The other product is water which will be liquid (l) since it is the solvent used to dissolve the substances.

<h3>LEARN MORE</h3>
  • Solubility Rules brainly.com/question/12984314
  • Net Ionic Equation brainly.com/question/12980075

Keywords: acid-base, neutralization, balancing equations, molecular equation

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