The one whose molar mass is smaller than sodium.
Fluorine is 19 g
Chlorine= 35.5 g
Bromine= 80 g
so in sodium fluoride, the percent of sodium is the largest.
Pressures simply add. If the partial pressure of gas is three and the partial pressure of water is five, the total pressure is eight. Find the partial pressure for water at the temperature of your experiment, subtract it from your <span>pressure reading.</span>
Answer:
4.90 moles of
will produce (9.8) moles of
,
(4.90) moles of
and
(39.2) moles of 
Explanation:
From the question we are told that
The number of moles of is 
The formation reaction of
is
From the reaction we see that
1 mole of
is formed by 2 moles of
1 mole of
and 4 
This implies that
4.90 moles of
will produce (2 * 4.90) moles of
,
(1 * 4.90) moles of
and
(8 * 4.90) moles of 
So
4.90 moles of
will produce (9.8) moles of
,
(4.90) moles of
and
(39.2) moles of 
B. Rotten orange is the correct answer. Hope this helps!
Explanation:
(w/w) % : The percentage mass or fraction of mass of the of solute present in total mass of the solution.

1) 100 g of 0.500% (w/w) NaI
Mass of solution = 100 g
Mass of solute = x
Required w/w % of solution = 0.500%


0.500 grams of solute needed to make 100 g of 0.500% (w/w) NaI.
2) 250 g of 0.500% (w/w) NaBr
Mass of solution = 250 g
Mass of solute = x
Required w/w % of solution = 0.500%


1.25 grams of solute needed to make 250 g of 0.500% (w/w) NaBr
3) 500 g of 1.25% (w/w) glucose
Mass of solution = 500 g
Mass of solute = x
Required w/w % of solution = 1.25%


6.25 grams of solute needed to make 500 g of 1.25% (w/w) (glucose)
4) 750 g of 2.00% (w/w) sulfuric acid.
Mass of solution = 750 g
Mass of solute = x
Required w/w % of solution = 2.00%


15.0 grams of solute needed to make 750 g of 2.00% (w/w) sulfuric acid.