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3 years ago

The wavelength of violet light is about 425 nm (1 nanometer = 1 × 10−9 m). what are the frequency and period of the light waves?

Physics

1 answer:

dexar [7]3 years ago

5 0

1) Frequency: $7.06\cdot 10^{14} Hz$

The frequency of electromagnetic radiation is given by:

$f=\frac{c}{\lambda}$

where

$c = 3 \cdot 10^8 m/s$ is the speed of light

$\lambda$ is the wavelength

In this case, the wavelength of the radiation is

$\lambda=425 nm=425\cdot 10^{-9} m$

Therefore the frequency is

$f=\frac{3\cdot 10^8 m/s}{425 \cdot 10^{-9} m}=7.06\cdot 10^{14} Hz$

2) Period: $1.42\cdot 10^{-15} s$

The period is equal to the reciprocal of the frequency of the wave:

$T=\frac{1}{f}$

Using the frequency we found previously, $f=7.06\cdot 10^{14} Hz$ , we find:

$T=\frac{1}{7.06\cdot 10^{14} Hz}=1.42\cdot 10^{-15} s$

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3 years ago

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3 years ago

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3 years ago

Two capacitors of capacitances 25 µF and 50 µF are connected in series with a 33-V battery. How much energy is stored in the 25-

torisob [31]

Answer:

6.05×10⁻³ J

Explanation:

Note: Two capacitors connected in series behaves like two resistors connected in parallel.

Using

1/Ct = 1/C1+1/C2

Ct = (C1×C2)/(C1+C2)............................ Equation 1

Where Ct = combined capacitance of the two capacitor, C1 = Capacitance of the first capacitor, C2 = capacitance of the second capacitor.

Given: C1 = 25 µF, C2 = 50 µF

Substitute into equation 1

Ct = (25×50)/(25+50)

Ct = 1250/75

Ct = 16.67 µF.

Using

Q = CV.................... Equation 2

Where Q = Charge, V = Voltage.

Given: V = 33 V, C = 16.67 µF = 16.67×10⁻⁶ F

Substitute into equation 2

Q = 33(16.67×10⁻⁶)

Q = 5.5×10⁻⁴ C.

Since both capacitors are connected in series, the same amount of charge flows through them.

Using,

E = 1/2Q²/C.................. Equation 3

Where E = Energy stored in the 25-µF capacitor

Given: Q =5.5×10⁻⁴ C, C = 25 µF = 25×10⁻⁶ F

Substitute into equation 3

E = 1/2(5.5×10⁻⁴)²/ 25×10⁻⁶

E = 6.05×10⁻³ J.

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3 years ago