It is a type capacitor is in which two metal plates arranged in such a way so that they are connected in parallel . The potential energy is stored in the capacitor will be 2.7×10⁻⁵.
<h3>What is parallel plate capacitor ?</h3>
It is an type capacitor is an in which two metal plates arranged in such a way so that they are connected in parallel and have some distance between them.
A dielectric medium is a must in between these plates. helps to stop the flow of electric current through it due to its non-conductive nature .
The given data in the problem is;
Q is the charge= 1.5 µC
V is the change in voltage across the plates is = 36 V.
U is the potential energy=?
The formula for the potential energy is given by;
Hence the potential energy is stored in the capacitor will be 2.7×10⁻⁵.
To learn more about the parallel plate capacitor refer to the link;
brainly.com/question/12883102
Hello!
By applying the third law of motion, your force and the wall's force are equal.
I hope this helps you! Have a great day!
- Mal
from the question you can see that some detail is missing, using search engines i was able to get a similar question on "https://www.slader.com/discussion/question/a-student-throws-a-water-balloon-vertically-downward-from-the-top-of-a-building-the-balloon-leaves-t/"
here is the question : A student throws a water balloon vertically downward from the top of a building. The balloon leaves the thrower's hand with a speed of 60.0m/s. Air resistance may be ignored,so the water balloon is in free fall after it leaves the throwers hand. a) What is its speed after falling for 2.00s? b) How far does it fall in 2.00s? c) What is the magnitude of its velocity after falling 10.0m?
Answer:
(A) 26 m/s
(B) 32.4 m
(C) v = 15.4 m/s
Explanation:
initial speed (u) = 6.4 m/s
acceleration due to gravity (a) = 9.9 m/s^[2}
time (t) = 2 s
(A) What is its speed after falling for 2.00s?
from the equation of motion v = u + at we can get the speed
v = 6.4 + (9.8 x 2) = 26 m/s
(B) How far does it fall in 2.00s?
from the equation of motion 
we can get the distance covered
s = (6.4 x 2) + (0.5 x 9.8 x 2 x 2)
s = 12.8 + 19.6 = 32.4 m
c) What is the magnitude of its velocity after falling 10.0m?
from the equation of motion below we can get the velocity
v = 15.4 m/s
Answer:
The average induced emf in the loop is 0.20 V
Explanation:
Given:
Radius of loop 
m
Magnetic field 
T
Change in time 
sec
According to the faraday's law,
Induced emf is given by
Where 
magnetic flux
( here 
)
Where 
We neglect minus sign because it's shows lenz law
V
Therefore, the average induced emf in the loop is 0.20 V
Answer: 5 gm/cc
Explanation:
200 gm/40 cc
= 5 gm/cc
