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Vadim26 [7]
3 years ago
7

If Earth were replaced by an object with the same mass but much smaller in size, would the moon continue to orbit the new object

, fall into it, or fly off into space? Why?
Physics
2 answers:
docker41 [41]3 years ago
7 0
It depends on, Depending on how much gravity the other object has depended if the moon will still orbit. Since Earth has a specific amount of gravity, the other object has to have the same number of EVERYTHING for it to work out.
Tanzania [10]3 years ago
3 0
I am pretty sure but not 100% that it would still continue to orbit
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The data table for the decomposition reaction of hydrogen peroxide H2 O2 shows how the reaction rate changes over time which sta
DedPeter [7]

I believe the answer is A.

4 0
2 years ago
Read 2 more answers
A force is a push or a pull. Under the right circumstances, anything can exert a force.
Sliva [168]

Answer:

Explanation:

the force that you applied caused the notebook to move.

the force applied on the notebook by the table causes it to stop moving.

this is because after sometime the book uses up the force and later the force you applied is less than that of the force by the table.

7 0
3 years ago
A 4.0-kg object is supported by an aluminum wire of length 2.0 m and diameter 2.0 mm. How much will the wire stretch?
forsale [732]

Answer:

The extension of the wire is 0.362 mm.

Explanation:

Given;

mass of the object, m = 4.0 kg

length of the aluminum wire, L = 2.0 m

diameter of the wire, d = 2.0 mm

radius of the wire, r = d/2 = 1.0 mm = 0.001 m

The area of the wire is given by;

A = πr²

A = π(0.001)² = 3.142 x 10⁻⁶ m²

The downward force of the object on the wire is given by;

F = mg

F = 4 x 9.8 = 39.2 N

The Young's modulus of aluminum is given by;

Y = \frac{stress}{strain}\\\\Y = \frac{F/A}{e/L}\\\\Y = \frac{FL}{Ae} \\\\e = \frac{FL}{AY}

Where;

Young's modulus of elasticity of aluminum = 69 x 10⁹ N/m²

e = \frac{FL}{AY} \\\\e = \frac{(39.2)(2)}{(3.142*10^{-6})(69*10^9)} \\\\e = 0.000362 \ m\\\\e = 0.362 \ mm

Therefore, the extension of the wire is 0.362 mm.

8 0
3 years ago
Which of the following is formed by constructive erosion? 1. delta 2. gully 3. rill 4. glacier
lana [24]
1. Delta, is formed by constructive erosion.
7 0
3 years ago
Find the difference between two masses measured as 123.6 grams and 115.972 grams. Express the answer to the correct number of si
xxTIMURxx [149]

Answer:

The difference is 7.6 grams.

Explanation:

In mathematics the difference of two numbers is express as the subtraction between them:

         

a-b

So to find out the difference between the two measured masses, a will be represented by 123.6 grams since is the bigger number, and b by 115.972 grams.

Therefore, it is get:

123.6grams-115.972grams = 7.6grams

<u>Hence, the difference is 7.6 grams. </u>

The result of 7.628 will be expressed as 7.6 to have the correct number of significant figures.          

 

Notice how that can be express in units of kilograms too since there is 1000 gram in 1 kilogram:

7.6grams . \frac{1Kg}{1000grams} ⇒ 7.6x10^{-3}Kg

8 0
3 years ago
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