Answer:
a) 2 (H+) ions
b) 1 (SO3²-) ions
c) 1.36 × 10^-22 grams.
Explanation:
According to this question, sulfurous acid has a chemical formula; H2SO3. It is made up of hydrogen and sulfite ion. Hydrogen ion (H+) is the cation while sulfite ion (SO32-) is the anion.
Based on the chemical formula, there are 2 moles of hydrogen ions that reacts with 1 mole of sulfite ion as follows:
2H+ + SO3²- → H2SO3
Hence;
- there are 2 hydrogen ions (2H+) present in H2SO3.
- there is 1 sulfite ion (SO3²-) present in H2SO3.
c) The mass of one formula unit of H2SO3 is calculated thus:
= 1.008 (2) + 32.065 + 15.999(3)
= 2.016 + 32.065 + 47.997
= 82.08 a.m.u
Since, 1 gram is = 6.02 x 10^23 a.m.u
82.08 a.m.u = 82.08/6.02 × 10^-23
= 13.6 × 10^-23
= 1.36 × 10^-22 grams.
Answer:
204g of NH3
Explanation:
The balanced equation for the reaction is given below:
N2 + 3H2 —> 2NH3
Next, we shall determine the number of mole NH3 produced by reacting 6moles of N2. This is illustrated below:
From the balanced equation above,
1 mole of N2 reacted to produce 2 moles of NH3.
Therefore, 6 moles of N2 will react to produce = 6 x 2 = 12 moles of NH3.
Finally, we shall convert 12 moles of NH3 to grams. This is illustrated below:
Number of mole of NH3 = 12 moles.
Molar mass of NH3 = 14 + (3x1) = 17g/mol
Mass of NH3 =..?
Mass = mole x molar mass
Mass of NH3 = 12 x 17
Mass of NH3 = 204g.
Therefore, 204g of NH3 will be produced from the reaction.
Answer:
the most best answer is 50.1 you never find such type of answer
The final temperature of the water will be 31.2 °C... i don’t know the second one sorry :(
