From Q = mcΔT, we can rearrange the equation to solve for mass, m = Q/cΔT. The specific heat capacity, c, of solid gold is 0.129 J/g °C. I'm assuming that the energy is given in joules, as it's not specified in the question as written.
m = Q/cΔT = (35.73 J)/(0.129 J/g °C)(40.85 °C - 0.85°C)
m = 6.92 g of gold was present
1- evaporation 2- transpiration 3-condensation 4- precipitation
By looking at the stochiometry, we can conclude that the ratio is 1 :1
2 moles of H2 react to form 2 moles of H2O
hope this helps
Answer:
a negative charge
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