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frutty [35]
3 years ago
10

How many moles of zinc are needed to react with 45.60 moles of nitric acid?

Chemistry
1 answer:
uranmaximum [27]3 years ago
3 0

Answer:

11.4 moles

Explanation:

Your chemical equation for the reaction of zinc and nitric acid will be

Zn  +  4 HNO₃  -->  Zn(NO₃)₂  +  2 NO₂  +  2 H₂O

To solve the problem, you need to use stoichiometry.  For every 1 mole of zinc, you will need 4 moles of nitric acid.  Divide 45.60 by 4.  Your answer should be 11.4 moles.

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