Answer:
d = 13 miles
Explanation:
Lets say the position of court house is origin in this case
her office is located at 4 miles west and 4 miles south of court house
so here we have coordinate of the office with respect to court house is given as
now the position of her home is located at 1 miles east and 8 miles north of the court house
so the coordinates of her home is given as
now the change in the position is given as the distance between office and home
Answer:
Power = 2.45Kw or 2450 Watts.
Explanation:
<u>Given the following data;</u>
Mass, m = 250kg
Height, h = 2m
Time, t = 2secs
We know that acceleration due to gravity, g is equal to 9.8m/s²
Power can be defined as the energy required to do work per unit time.
Mathematically, it is given by the formula;
But Energy = mgh
Substituting into the equation, we have
Power = 2450 Watts
To convert to kilowatt (Kw), we would divide by 1000
Power = 2450/1000
Power = 2.45Kw.
Therefore, the average power output of the weightlifter is 2.45 Kilowatts.
Answer:
cost of running the furnace during January is $5619.62
Explanation:
given data
runs a day = 13 hours
January days = 31 days
resistance = 7.2 ohm
current = 16.7 A
cost of electricity = $0.10/kWh
to find out
cost of running the furnace during January
solution
first we get her power consumed by furnace that is
Power consumed = ........1
put here value we get
Power consumed =
Power consumed = 38.7347 W
and
Power consumed by furnace in one hour is
Power consumed by furnace in one hour is = Power consumed × 3600
Power consumed by furnace in one hour is = 38.7347 × 3600
Power consumed by furnace in one hour is 139.445kWh
and
Power consumed by furnace in the month of January is
Power consumed by furnace in the month of January = 139.445kWh × 13 hours × 31 days
Power consumed by furnace in the month of January = 56196.335 kWh
so
cost of running the furnace during January is = $0.10/kWh × 56196.335 kWh
cost of running the furnace during January is $5619.62
