1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Mumz [18]
3 years ago
9

The materials that made up the solar nebula can be categorized into the four general types as follows. Rank these materials from

left to right based on their abundance in the solar nebula, from highest to lowest.
Physics
1 answer:
san4es73 [151]3 years ago
5 0

Answer:

  1. Hydrogen and Helium
  2. Rock
  3. Metals
  4. Hydrogen compounds

Ranked from left to right based on their abundance in the solar nebula:

Hydrogen and Helium-Hydrogen compounds-Rocks-Metals

I hope you find this information useful and interesting! Good luck!

You might be interested in
A box rests on top of a flat bed truck. The box has a mass of m = 16.0 kg. The coefficient of static friction between the box an
3241004551 [841]

Answer:

1) 1.31 m/s2

2) 20.92 N

3) 8.53 m/s2

4) 1.76 m/s2

5) -8.53 m/s2

Explanation:

1) As the box does not slide, the acceleration of the box (relative to ground) is the same as acceleration of the truck, which goes from 0 to 17m/s in 13 s

a = \frac{\Delta v}{\Delta t} = \frac{17 - 0}{13} = 1.31 m/s2

2)According to Newton 2nd law, the static frictional force that acting on the box (so it goes along with the truck), is the product of its mass and acceleration

F_s = am = 1.31*16 = 20.92 N

3) Let g = 9.81 m/s2. The maximum static friction that can hold the box is the product of its static coefficient and the normal force.

F_{\mu_s} = \mu_sN = mg\mu_s = 16*9.81*0.87 = 136.6N

So the maximum acceleration on the block is

a_{max} = F_{\mu_s} / m = 136.6 / 16 = 8.53 m/s^2

4)As the box slides, it is now subjected to kinetic friction, which is

F_{\mu_s} = mg\mu_k = 16*9.81*0.69 = 108.3 N

So if the acceleration of the truck it at the point where the box starts to slide, the force that acting on it must be at 136.6 N too. So the horizontal net force would be 136.6 - 108.3 = 28.25N. And the acceleration is

28.25 / 16 = 1.76 m/s2

5) Same as number 3), the maximum deceleration the truck can have without the box sliding is -8.53 m/s2

3 0
3 years ago
We need to find the launch velocity of our new marble launcher. we know that it will launch a 25g marble to a distance of 73 cm,
White raven [17]

The launch velocity of the marble launcher is 34.65 m/s

Given that the launch velocity of marble launcher, launches a 25g marble to a distance of 73 cm (0.73 m) and the marble roll up to 6.2 meters before stopping. The launch height is 20 cm (0.2 m).

The time for landing can be calculated by the second equation of motion formula:

h = ut + \frac{1}{2}gt^{2}

Let u = 0

0.2 = 0×t + \frac{1}{2} × 9.8 × t^{2}

t^{2} = \frac{0.2}{4.9}

t^{2} = 0.04

t = 0.2s

Now, the launch velocity of the marble launcher can be calculated by:

Speed = Distance / Time

Speed = \frac{0.73 + 6.3}{0.2}

Speed = \frac{6.93}{0.2}

Speed = 34.65 m/s

Therefore, the launch velocity of the marble launcher is 34.65 m/s

Know more about Launch velocity: -brainly.com/question/18883779

#SPJ9

3 0
1 year ago
9. A Veggie meatball with v = 5.0 m/s rolls off a 1.0 m high table. How long does it take to hit the floor if no one sneezes? Wh
Paha777 [63]

By Considering the vertical distance and both vertical and horizontal final velocity, the time t = 0.45 s and Velocity V = 6.7 m/s

Given that a Veggie meatball with v = 5.0 m/s rolls off a 1.0 m high table.

Height h = 1.0 m

As the ball rolls off the table, it will be fallen under gravity. Where

g = 9.8 m/s^{2}

Initial vertical velocity u_{y} = 0

Initial horizontal velocity u_{x} = 5 m/s

Considering the vertical distance, the formula to use to calculate the time will be;

h = ut + 1/2gt^{2}

1 = 0 + 1/2 x 9.8t^{2}

1 = 4.9t^{2}

t^{2} = 1/4.9

t = \sqrt{0.204}

t = 0.45 seconds

It takes 0.45 seconds to hit the floor if no one sneezes.

To calculate its velocity when it hits the floor, we will need to calculate for both vertical and horizontal final velocity and find the resultant velocity of the two.

Vertical component

V_{y} = U_{y} + gt

V_{y} = 0 + 9.8(0.45)

V_{y} = 4.41 m/s

Horizontal component

V_{x} = u_{x} + at

but a = 0

V_{x} = 5 m/s

Final velocity V = \sqrt{5^{2} + 4.41^{2}  }

V = 6.67 m/s

Therefore, it will hit the floor at a velocity of 6.7 m/s

Learn more here: brainly.com/question/5063616

8 0
2 years ago
Tell the order of vessels a blood Cell travels through starting from the heart.
Natalka [10]
Arterie
cwamus
capillaries
phloprant
veins
piscas
7 0
3 years ago
Gravity is a force. Gravity is also an example of __________________. . . A.. a theory. . B.. an established procedure. . C.. a
MissTica
The correct answer to this question is C - Gravity is a force. Gravity is also an example of a universal law. Well, according to Isaac Newton, anyway. According to Newton's Law of Universal Gravitation, 'every point mass attracts every single point mass by a force pointing along the line intersecting both paths.'
<span />
7 0
3 years ago
Other questions:
  • Select the correct statement to describe when a sample of liquid water vaporizes into water vapor. Question 12 options: Temperat
    9·1 answer
  • Are the Sun's rays like mechanical or electromagnetic waves
    8·2 answers
  • U. A hockey player takes a slap shot at a puck at rest on
    14·1 answer
  • Newton
    10·1 answer
  • What is dark matter consisted of?
    11·2 answers
  • You want to calculate the displacement of an object thrown over a bridge. Using -10m/s^2 for acceleration due to gravity, what w
    8·1 answer
  • After traveling for 6.0 seconds, a runner reaches 10m/s. What is the runner's acceleration?
    5·1 answer
  • Assume that the polymer material has a constant refractive index of 1.5. For light of 600nm wavelength at normal incidence, what
    15·1 answer
  • Calculate the kinetic energy of a 20-kg sled moving 28.0 m/s. Show your work in the space to the right.
    10·1 answer
  • 1. The magnitude of the electrostatic force a charge particle exerts on a 5.0nC particle 0.20m away from it is 18N. Find the mag
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!