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Anastaziya [24]
2 years ago
9

Light travels 300 000 000 m/s and one year has approximately 32 000 000 second a light year is the distance light travels in one

year
Physics
1 answer:
Lelu [443]2 years ago
8 0

Explanation:

It is given that,

Speed of light, v=300 000 000\ m/s=3\times 10^8\ m/s

Seconds in 1 year, t=32 000 000=32\times 10^6\ s

We need to find the distance traveled by light in one year. Speed of an object is given by :

v=\dfrac{d}{t}

So,

d=v\times t\\\\d=3\times 10^8\times 32\times 10^6\\\\d=9.6\times 10^{15}\ m

Since,

1\ \text{light year}=9.46\times 10^{15}\ m\\\\1\ m=\dfrac{1}{9.46\times 10^{15}}\ \text{ly}\\\\9.6\times 10^{15}\ m=\dfrac{9.6\times 10^{15}}{9.46\times 10^{15}}\\\\d=1.01\ \text{ly}

So, the distance covered by light is 1.01 light years.

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A rocket on Earth experiences an upward applied force from its thrusters. As a result of this force, the rocket accelerates upwa
gayaneshka [121]

Answer:

F=m(11.8m/s²)

For example, if m=10,000kg, F=118,000N.

Explanation:

There are only two vertical forces acting on the rocket: the force applied from its thrusters F, and its weight mg. So, we can write the equation of motion of the rocket as:

F-mg=ma

Solving for the force F, we obtain that:

F=ma+mg=m(a+g)

Since we know the values for a (2m/s²) and g (9.8m/s²), we have that:

F= m(2m/s^{2}+9.8m/s^{2})\\\\F=m(11.8m/s^{2})

From this relationship, we can calculate some possible values for F and m. For example, if m=10,000kg, we can obtain F:

F=(10,000kg)(11.8m/s^{2})\\\\F=118,000N

In this case, the force from the rocket's thrusters is equal to 118,000N.

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